Start at (0, 135) and work your way down 15 and over one each time. Your next point would be (1, 120)
Answer:
![y=2x+7](https://tex.z-dn.net/?f=y%3D2x%2B7)
Step-by-step explanation:
<u><em>The correct question is</em></u>
what is the equation for a line passing through (-2,3) and perpendicular to y= -1/2<em>x</em>+1 ?
Remember
If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes are equal to -1)
The slope of the given line is m=-1/2
so
the opposite reciprocal is m=2
<em>Find the equation of the line in point slope form</em>
![y-y1=m(x-x1)](https://tex.z-dn.net/?f=y-y1%3Dm%28x-x1%29)
we have
![m=2\\point\ (-2,3)](https://tex.z-dn.net/?f=m%3D2%5C%5Cpoint%5C%20%28-2%2C3%29)
substitute
![y-3=2(x+2)](https://tex.z-dn.net/?f=y-3%3D2%28x%2B2%29)
<em>Convert to slope intercept form</em>
![y=mx+b](https://tex.z-dn.net/?f=y%3Dmx%2Bb)
isolate the variable y
![y-3=2x+4](https://tex.z-dn.net/?f=y-3%3D2x%2B4)
![y=2x+4+3](https://tex.z-dn.net/?f=y%3D2x%2B4%2B3)
![y=2x+7](https://tex.z-dn.net/?f=y%3D2x%2B7)
The first problem, all you need to do is combine like terms then isolate the n:
4n-2n=4
~subtract 2n from 4n (2n)
2n=4
~then divide both sides of the equation by 2 to isolate the n
n=4
The second problem follows the same steps of combining like terms and isolating the variable. Here, you'll have to combine 2 like terms:
-12=2+5v+2v
~first combine the variables which is just 5v+2v which is 7v
-12=2+7v
~then subtract 2 from both sides to isolate the 7v
-14=7v
~then divide both sides by 7 to isolate the v and get your answer
-2=v
Hope that helped!
Using the z-distribution, a sample of 142,282 should be taken, which is not practical as it is too large of a sample.
<h3>What is a z-distribution confidence interval?</h3>
The confidence interval is:
![\overline{x} \pm z\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=%5Coverline%7Bx%7D%20%5Cpm%20z%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
The margin of error is:
![M = z\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
In which:
is the sample mean.
is the standard deviation for the population.
Assuming an uniform distribution, the standard deviation is given by:
![S = \sqrt{\frac{(4 - 0)^2}{12}} = 1.1547](https://tex.z-dn.net/?f=S%20%3D%20%5Csqrt%7B%5Cfrac%7B%284%20-%200%29%5E2%7D%7B12%7D%7D%20%3D%201.1547)
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
The sample size is found solving for n when the margin of error is of M = 0.006, hence:
![M = z\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
![0.006 = 1.96\frac{1.1547}{\sqrt{n}}](https://tex.z-dn.net/?f=0.006%20%3D%201.96%5Cfrac%7B1.1547%7D%7B%5Csqrt%7Bn%7D%7D)
![0.006\sqrt{n} = 1.96 \times 1.1547](https://tex.z-dn.net/?f=0.006%5Csqrt%7Bn%7D%20%3D%201.96%20%5Ctimes%201.1547)
![\sqrt{n} = \frac{1.96 \times 1.1547}{0.006}](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D%20%3D%20%5Cfrac%7B1.96%20%5Ctimes%201.1547%7D%7B0.006%7D)
![(\sqrt{n})^2 = \left(\frac{1.96 \times 1.1547}{0.006}\right)^2](https://tex.z-dn.net/?f=%28%5Csqrt%7Bn%7D%29%5E2%20%3D%20%5Cleft%28%5Cfrac%7B1.96%20%5Ctimes%201.1547%7D%7B0.006%7D%5Cright%29%5E2)
n = 142,282.
A sample of 142,282 should be taken, which is not practical as it is too large of a sample.
More can be learned about the z-distribution at brainly.com/question/25890103
#SPJ1
Answer:
32.6 - y= 10.2
Step-by-step explanation:
The equation to solve this problem can be written as
32.6 - y= 10.2
Where y is the number that was substracted from 32.6.
If we make y subject of formula we have
y= (32.6-10.2)
y=22.4
Which means the number that was substracted from 32.6 is 22.4 and there difference is 10.2