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aleksley [76]
3 years ago
14

Please help need this done ASAP ​

Mathematics
1 answer:
Vaselesa [24]3 years ago
3 0

Answer:

a) 56548.7 cm³

b) 13 minutes

Step-by-step explanation:

a) The volume will be 2/3 pi r³ (which is the given formula divided by 2 since we only have half a sphere)

Fill in r=30 gives: 56548.7 cm³

b) 56548.7 cm³ divided by 4500 cm³/min = 12.6 ≈ 13 minutes

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What does recursive mean.?
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3 years ago
Fred and Ben each ran laps around the track. Fred completed his run in 16 minutes. Ben completed his run in 3/4 of the amount of
m_a_m_a [10]

Answer:

Time required by Ben was 12 minutes.

Step-by-step explanation:

Given:

Time Required for Fred = 16 mins

Ben completed his run in 3/4 of the amount of time of Freds run.

We need to find the time required by Ben.

Now Given that;

Ben completed his run in 3/4 of the amount of time of Freds run.

It means that time required by Ben is equal to 3/4  times time required by Fred.

Time required by Ben = \frac{3}{4}\times  Freds \ run

Time required by Ben = \frac{3}{4}\times 16 = 12\ mins

Hence Time required by Ben was 12 minutes.

7 0
3 years ago
Sara takes 1/6 of an hour to vacuum his moms car it takes 4 times that long to wash the car then it takes you to wax the car twi
Nataly [62]
<h2>Answer:</h2><h2>2 hours & 10 minutes </h2><h2>Step-by-step explanation:</h2><h2>1/6 of an hour is 10 minutes. She vacuumed for 10 minutes. It took 4 times as long to wash the car so 10 * 4 = 40. She washed the car for 40 minutes. It took her twice as long to wax the car as it did for her to wash it so 40 * 2 = 80. She waxed the car for 80 minutes. 10 + 40 + 80 = 130 minutes or 2 hours and 10 minutes. </h2>
3 0
3 years ago
At what angle does a diffraction grating produce a second-order maximum for light having a first-order maximum at 20.0 degrees?
hichkok12 [17]

Answer:

At 43.2°.

Step-by-step explanation:

To find the angle we need to use the following equation:

d*sin(\theta) = m\lambda

Where:

d: is the separation of the grating

m: is the order of the maximum

λ: is the wavelength

θ: is the angle              

At the first-order maximum (m=1) at 20.0 degrees we have:

\frac{\lambda}{d} = \frac{sin(\theta)}{m} = \frac{sin(20.0)}{1} = 0.342

Now, to produce a second-order maximum (m=2) the angle must be:

sin(\theta) = \frac{\lambda}{d}*m

\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.    

I hope it helps you!                                                        

6 0
3 years ago
Hi pls help this is TIMED
alexandr1967 [171]

What is the question you have?

3 0
3 years ago
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