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joja [24]
3 years ago
10

Given the sequence 4,16,64

Mathematics
1 answer:
umka2103 [35]3 years ago
4 0
A. Geometric

b. a curve sloping steeply upwards  (exponential)

c. nth term an = a1r^(n-1)

 nth term  = 4(4)^(n-1)
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Correct I complety agree

Step-by-step explanation:

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Answer: 20−12/3=?16

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The table shows ordered pairs of the function y=8-2 x . What is the value of y when x=8 ?
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Your answer is given below:

Step-by-step explanation:

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135°

Step-by-step explanation:

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A hospital’s financial reimbursement payor mix indicates 35% of the patients have Medicare and 15% have Medicaid. Of those who h
Damm [24]

Using conditional probability, it is found that there is a 0.035 = 3.5% probability that a hospital patient has both Medicare and Medicaid.

<h3>What is Conditional Probability?</h3>
  • <em>Conditional probability</em> is the <u>probability of one event happening, considering a previous event</u>. The formula is:

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem, the events are:

  • Event A: Patient has Medicare.
  • Event B: Patient has Medicaid.

For the probabilities, we have that:

  • 35% of the patients have Medicare, hence P(A) = 0.35.
  • Of those who have Medicare, there is a 10% chance they also have Medicaid, hence P(B|A) = 0.1.

Then, applying the <em>conditional </em>probability:

P(B|A) = \frac{P(A \cap B)}{P(A)}

0.1 = \frac{P(A \cap B)}{0.35}

P(A \cap B) = 0.35(0.1)

P(A \cap B) = 0.035

0.035 = 3.5% probability that a hospital patient has both Medicare and Medicaid.

You can learn more about conditional probability at brainly.com/question/14398287

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3 years ago
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