We can use the ideal gas law equation to find the number of moles in the sample. PV = nRT where P - pressure 1 atm x 101 325 Pa/atm = 101 325 Pa V - volume - 2.05 x 10⁻³ m³ n - number of moles R - universal gas constant - 8.314 Jmol⁻¹K⁻¹ T - temperature - 309 K 101 325 Pa x 2.05 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 309 K n = 0.081 mol answer is 0.081 mol
<span>8.21 L of C3H8(g)
Lets take c as the molar volume at that temperature. c L <><> 5c L C3H8 (g) + 5O2 (g) --> 3CO2 + 4H2O + Q 8.21 L <><> x L x = (8.21 * 5c)/c = 8.21 * 5 = 41.05 L O2 consumed for a 100% yield.</span>
