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Pachacha [2.7K]
3 years ago
8

Initial temperature of metal= 100 C°

Chemistry
1 answer:
Vilka [71]3 years ago
3 0

Water is 22.4

Final for both us 27.1

Explanation:

I just finished this part of the lab

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FrozenT [24]

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It is so because when a tree getting struck by lightning, it encountered a strong force of power but no new substance is formed here. So it is a physical change, if it is a chemical change then a new substance must formed here. So when a tree getting struck by lightning, it is an example of a physical change.

7 0
3 years ago
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3 years ago
4 Al + 3O2 → 2Al2O3 If 14.6 grams Al are reacted, how many liters of O2 at STP would be required?
melomori [17]

Answer: 9.08 L

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}\times{\text{Molar Mass}}    

\text{Moles of} Al=\frac{14.6g}{27g/mol}=0.54moles

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According to stoichiometry :

4 moles of Al require  = 3 moles of O_2

Thus 0.54 moles of Al will require=\frac{3}{4}\times 0.54=0.405moles  of O_2

Standard condition of temperature (STP)  is 273 K and atmospheric pressure is 1 atm respectively.

According to the ideal gas equation:

PV=nRT

P = Pressure of the gas = 1 atm

V= Volume of the gas = ?

T= Temperature of the gas = 273 K      

R= Gas constant = 0.0821 atmL/K mol

n=  moles of gas= 0.405

V=\frac{nRT}{P}=\frac{0.405\times 0.0821\times 273}{1}=9.08L

Thus 9.08 L of O_2 at STP would be required

6 0
3 years ago
Type of bond between na+1 ion and Cl-1 ion is ion
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A neutral sodium atom, for example, contains 11 protons and 11 electrons. By removing an electron from this atom we get a positively charged Na+ ion that has a net charge of +1. Atoms that gain extra electrons become negatively charged. A neutral chlorine atom, for example, contains 17 protons and 17 electrons.

6 0
3 years ago
Why do you need many different indicators to span the entire ph spectrum?
marin [14]
The answer is each indicator has a narrow range.  We need many different indicators to span the entire ph spectrum because each indicator has a narrow range.
4 0
3 years ago
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