Distance = 100 m = 100/1000 = 0.1 km speed of train = 50 km/hr speed of horse = 56 km/hr resultant speed = (56 – 50) 6 km/hr time = distance/speed time = 0.1/6 = 1/60 hr = 1 min
Answer:
Step-by-step explanation:
We will use 2 coordinates from the table along with the standard form for an exponential function to write the equation that models that data. The standard form for an exponential function is
where x and y are coordinates from the table, a is the initial value, and b is the growth/decay rate. I will use the first 2 coordinates from the table: (0, 3) and (1, 1.5)
Solving first for a:
. Sine anything in the world raised to a power of 0 is 1, we can determine that
a = 3. Using that value along with the x and y from the second coordinate I chose, I can then solve for b:
. Since b to the first is just b:
1.5 = 3b so
b = .5
Filling in our model:

Since the value for b is greater than 0 but less than 1 (in other words a fraction smaller than 1), this table represents a decay function.
Answer:
I think you forgot the context or image of that.
Answer:
2
Step-by-step explanation:
Perimeter of a rectangle = 2(length + breadth)
=> 2{2x + (x + 4)) = 20
=> (2x + x + 4) = 20/2 = 10
=> 3x + 4 = 10
=> 3x = 10 - 4 = 6
=> x = 6/3 = 2
Here, according to the diagram
Length = 2x = 2(2) = 4
Breadth = x + 4 = 2+4 = 6
But breadth should always be lesser than the length. From this, it can be concluded that the actual breadth is 2x and actual length is x + 4, for perimeter to be 20.
Answer: ![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)
Step-by-step explanation:

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;


Divide by m to isolate
.


To eliminate the square and isolate v, extract the square root.
![\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3D%5Csqrt%5B%5D%7Bv%5E2%7D)
![\sqrt[]{\frac{2K}{m} }=v](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3Dv)
let's rewrite it in a way that v is in the left side.
![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)