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3 years ago

02.27.49

Mathematics

1 answer:

gavmur [86]3 years ago

5 0

Answer:

Rectangular prism, triangular prism, cylinder

Step-by-step explanation:

has base in the form of rectangle,so when cut perpendicular to base,the base as well as other faces, will be in the shape of Rectangle. Same for the triangular prism and cylinder.

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Can anyone please help me with these

Readme [11.4K]

Answer:

4(x+2) = 4*x + 4*2 = 4x+8

3(a+2) = 3*a + 3*2 = 3a + 6

2(x+3) = 2*x + 2*3 = 2x +6

Hope this help you :3

6 0

4 years ago

Read 2 more answers

List the single-digit divisors of 2100. I really need help

liberstina [14]

Answer:

1, 2, 3, 4, 5, 6, 7

Step-by-step explanation:

Prime factors of 2100 are:

2100 = 2*2*3*5*5*7

The single-digit divisors are:

1, 2, 3, 2*2= 4, 5, 2*3= 6, 7

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Another solution is you divide 2100 by all numbers 1 through 9 and list those divisible:

2100/1 = 2100, yes
2100/2 = 1050, yes
2100/3 = 700, yes
2100/4 = 525, yes
2100/5 = 420, yes
2100/6 = 350, yes
2100/7 = 300, yes
2100/8 = 262.5, no
2100/9 = 233.33, no

So all the numbers from 1 to 7

5 0

3 years ago

F number please help me

Morgarella [4.7K]

Answer:

-15/16 or -0.9375

Step-by-step explanation:

3/5x=6 +7x

3x=30+35x

3x-35x=30

-32x=30

x= -15/16

6 0

4 years ago

Read 2 more answers

What is the length of the segment, endpoints of which are intersections of parabolas y=x^2− 11/4 x− 7/4 and y=− 7/8 x^2+x+ 31/8

kobusy [5.1K]

Answer:

The length of line segment is 5

Step-by-step explanation:

we are given equation of parabolas as

$y=x^2-\frac{11}{4}x-\frac{7}{4}$

$y=-\frac{7}{8}x^2+x+\frac{31}{8}$

Firstly, we will find intersection points

we can set them equal

and then we can solve for x

$x^2-\frac{11}{4}x-\frac{7}{4}=-\frac{7}{8}x^2+x+\frac{31}{8}$

Multiply all sides by 8

$x^2\cdot \:8-\frac{11}{4}x\cdot \:8-\frac{7}{4}\cdot \:8=-\frac{7}{8}x^2\cdot \:8+x\cdot \:8+\frac{31}{8}\cdot \:8$

$8x^2-22x-14=-7x^2+8x+31$

$15x^2-30x-45=0$

now, we can factor it

$15(x^2-2x-3)=0$

$15(x-3)(x+1)=0$

$x=-1,x=3$

now, we can find y-values

At x=-1:

$y=(-1)^2-\frac{11}{4}(-1)-\frac{7}{4}$

y=2

so, we get point as

(-1,2)

At x=3:

$y=(3)^2-\frac{11}{4}(3)-\frac{7}{4}$

y=-1

so, we get point as

(3,-1)

now, we can find distance between these two points

(-1,2)

x1=-1 , y1=2

(3,-1)

x2=3 , y2=-1

now, we can find distance

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

now, we can plug values

$D=\sqrt{(3+1)^2+(-1-2)^2}$

$D=5$

So,

The length of line segment is 5

6 0

3 years ago

Someone help me please! :D

alexandr402 [8]

The angles of a quadrilateral add to 360, so we can solve for x by adding the 4 angle measures together and setting it equal to 360:

90 + 140 + (x - 10) + (x - 20) = 360

Combine like terms:

230 + 2x - 30 = 360

200 + 2x = 360

200 - (200) + 2x = 360 - (200)

2x = 160

Divide both sides by 2:

2x/(2) = 160/(2)

x = 80

3 0

3 years ago