Well it depends...... (.5= 1/2)
Answer:
Tema = 26 years
Juma = 13 years
Abdul = 26 years
Step-by-step explanation:
Let their ages be represented as:
Tema = x
Juma = y
Abdul = z
From the question, we are told that:
Juma is twice as old as Abdul
y = 2z
z = y/2
= 0.5y
And Juma is a half times as old as Tema.
y = 1/2x
y = 0.5x
x = y/0.5
x = 2y
Hence,
x + y + z = 65
2y + y + 2y = 65
= 5y = 65
y = 65/5
y = 13 years
Since y = Zuma's age, Zuma is 13 years old
From the above question
Since 2y = z
y = 13
2 × 13 = z
z = 26
Since z = Abdul's age, Abdul is 26 years old
From the above question
x = 2y
y = 13 years
x = 2 × 13 years
x = 26 years.
Since x = Tema's age
Tema is 26 years.
Therefore, their present ages are:
Tema = 26 years
Juma = 13 years
Abdul = 26 years
Answer:
As an improper fraction: 8463/32
As a mixed number 264 15/32
Step-by-step explanation:
1. Multiply the base number times the denominator, then add the numerator to that number, and put it over the original denominator.
2. Do this for all of the numbers
3. multiply straight across, top*top*top, then bottom*bottom*bottom numbers. That number will be your improper fraction. Then divide that top number by the bottom denominator, take it out, leave the remainder as the numerator, and you have your mixed number.
Solution:
As given Rectangle ABCD is reflected over the y- axis.
When a shape or geometrical figure is reflected through a line it's distance that is distance of image from line and distance of Pre-image from that line is always same.Also perpendicular distance of vertices of any polygon that is considered for reflection has same distance from that line after reflection and before reflection.
Suppose the coordinate of A be (x,y) and considering Rectangle A B CD lie in first quadrant then when it is reflected through y - axis that is through the line x=0, it's new coordinate will become A' (-x,y).
If rectangle is in second quadrant having Vertices that is vertices of A (-x,y) then reflected over line that is x=0,→ y axis then Vertices of A' (x,y).
If rectangle is in third quadrant having Vertices that is vertices of A (-x,-y) then reflected over line that is x=0,→ y axis then Vertices of A' (x,-y).
If rectangle is in fourth quadrant having Vertices that is vertices of A (x,-y) then reflected over line that is x=0,→y axis then Vertices of A' (-x,-y).