The given equations are y= 6x^2+1 and y=x^2+4
Both the equations equal y so we can make them equal
6x^2+1=x^2+4
To bring x term on one side we subtract x^2 both sides
6x^2-x^2+1=4
5x^2+1=4
To isolate x term we subtract 1 both sides
5x^2=4-1
5x^2=3
Dividing by 5 both sides
X^2=3/5
Taking root of both sides we have:
X=±√⅗
Substituting x value to find y
When x=+√⅗=0.7745
Y= 6x^2+1
Y=6(3/5)+1
Y= 18/5+1
Y=23/5 =4.6
When x= -√⅗=-0.7745
Y= 6(3/5)+1
Y=23/5=4.6
Point of intersections are ( 0.7745,4.6) and (-0.7745,4.6)
Answer:
-12
Step-by-step explanation:
7 1/2 ÷(4 1/2 - 5 1/8)
7 1/2 ÷ -5/8
7 1/2* -8/5
-12
By the ASA postulate we figure that:
Angles C and D are equal (noted by the line through these angles)
Lines CB and DE are parallel and equal in length (noted by the double line through these sides)
Angle B and E are both 90° (noted by the square at each of these angles)
From this information, we can say that triangle CBA = triangle DEA is true.
Answer:
16.40
Step-by-step explanation:
use Pythagorean theorem
∠FEG is an exterior angle.
An exterior angle of a triangle is equal to the sum of the opposite interior angles, so
2x + x = x + 40
3x = x + 40
3x - x = 40
2x = 40
x = 20
m∠FEG = x+40 = 20+40 = 60°
