Answer:
y = -9
Step-by-step explanation:
a line perpendicular to the x-axis is a horizontal line (which means the slope is zero) which pass through the y-axis at -9
Answer:
0.87 1.0
0.13
Step-by-step explanation:
0.13 dont have a calculator
A turning point occurs when the velocity is equal to zero, but the acceleration is not equal to zero.
t(x)=(x+5)^3+7
dt/dx=3(x+5)^2
d2t/dx2=6(x-5)
dt/dx=0 only when x=-5
However, since d2t/dx2(-5)=0, this point is an inflection point, not a turning point.
So there is no turning point for this function.
Now in this problem, it is even easier than the above to show that there is no turning point. A turning point by definition is when the derivative or velocity changes sign. Since in this case v=3(x+5)^2, for any value of x, v≥0, and thus never becomes negative, so it never changes from a positive to negative velocity because velocity in this instance is a squared function.
100-28-48-8= 16%
Hope it helped
