Hip Breadths and Aircraft Seats
Engineers want to design seats in commercial aircraft so that they are wide enough to fit 98% of all males. (Accommodating 100% of males would be too expensive.) Men have hip breadths that are normally distributed with a mean of 14.4 in. and a standard deviation of 1.0 in. Find P 98. That is, find the hip breadth for men that separates the smallest 98% from the largest 2%.
You’re going it plug in the inputs for every input for the letter x. So the first one, fx= -4(-2)+1= 9. The second one fx= -4(0)+1=1. The third one fx= -4(5)+1=19.
Answer:
(2n+6)^2
Step-by-step explanation:
To solve this, you can use the given formula: x^2 + 2xy + y^2
In this case, 4n^2 is x^2, 24n is 2xy, and 36 is y^2. The next step is:
(2n)^2 + 2(2n)(6) + (6)^2
Since this equation fits into this formula ( x^2 + 2xy + y^2), we can do:
(2n+6)(2n+6) =
(2n+6)^2
Hence, the answer is (2n+6)^2
Answer:
the first one is 84
Step-by-step explanation:
subtract 145-61 then you get 84for the missing angle.
