3 years ago

How was the gravitational force related to the distance between two objects

Physics

1 answer:

PIT_PIT [208]3 years ago

4 0

varies as one over the distance squared

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Plz help me plzzz. I'm begging you

Gnom [1K]

Answer:

a then c then b

Explanation:

6 0

3 years ago

a. A rectangular pen is built with one side against a barn. 1900 m of fencing are used for the other three sides of the pen. Wha

Natalka [10]

Answer:

475 m , 950 m

Explanation:

Let l be the length of the side perpendicular to the barn.

1900-2l = length of the side parallel to the barn

Area A= l( 1900-2l)

A= 1900l-2l^2

now, the maximum value of l ( the equation being quadratic)

l_max= -b/2a

a= 2

b=1900

l_max= -1900/4= 475 m

then 1900-2l= 1900-2×(475) = 950 m

So, the dimensions that maximize area are

950 and 475

Now. A_max = -2( l_max)^2+1900×l_max

A_max= -2(475)^2+1900×475

A_max= 451250 m^2

or, 475×950 = 451250 m^2

6 0

4 years ago

What is the frequency of a wave traveling at 300,000,000 m/s with a wavelength of .0025 m/cycle? Please help me !!

Lelu [443]

Answer:

its 00.0035474

Explanation:

..... .. . . .. . . . . .. .

8 0

4 years ago

The element magnesium has 2 valence electrons. What is the most likely charge on a magnesium ion?

RSB [31]

The charge is 2+

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5 0

4 years ago

A sack of potatoes weighing 16.0-kg falls from a very tall building. At a certain point at the motion downwards, its measured ac

Vitek1552 [10]

Answer:

The terminal speed is 74.833 m/s

Explanation:

The drag force is equal to square of speed:

Fdrag = k*v²

According Newton`s law:

Fnet = m*a

m*g - k*v² = m*a

$k=\frac{m(g-a)}{v^{2} }$

$k=\frac{16*(9.8-4.6)}{54.2^{2} } =0.028$

If terminal speed, the net force is zero.

$kv_{t} ^{2} =mg\\v_{t} =\sqrt{\frac{mg}{k} } =\sqrt{\frac{16*9.8}{0.028} } =74.833m/s$

7 0

4 years ago