Answer:
<em>The range is 15.15 m and the time in the air is 1.01 s</em>
Explanation:
<u>Horizontal Motion</u>
When an object is thrown horizontally (with angle 0°) with a speed v from a height h, it follows a curved path ruled exclusively by gravity until it eventually hits the ground.
The range or maximum horizontal distance traveled by the object can be calculated as follows:
To calculate the time the object takes to hit the ground, we use the equation below:
The cannon is shot from a height of h=5 m with an initial speed of v=15 m/s. The range is calculated below:
d = 15.15 m
The time in the air is:
t = 1.01 s
The range is 15.15 m and the time in the air is 1.01 s
Answer: The net displacement is 6.40meters
Explanation:
Answer:
don't know I just want point for answers
Answer:
41.8m/s^2
Explanation:
Since the dragster starts from rest, initial velocity (u) = 0m/s, final velocity (v) = 25.9m/s, time (t) = 0.62s
From the equations of motion, v = u + at
a = (v - u)/t = (25.9 - 0)/0.62 = 25.9/0.62 = 41.8m/s^2