<span>we know that cos(a - b) = cos(a) cos(b) + sin(a) sin(b)
given a = π/3 and b = π/5
cos(π/3) cos(π/5) + sin(π/3) sin(π/5) = cos((π/3) - (π/5) = cos(2π/15)
hope it helps
</span>
Here x^3-27=0 can be written as
x^3=27 and it also can be,
x^3=3^3
then on comparing both we got ,
x=3..
Hope it will satisfy you
Answer:
x = 3
Step-by-step explanation:
Answer:
Tabitha received 60 votes.
Step-by-step explanation:
Tabitha received 30% of 200 votes. (I had this question and you forgot to mention how many people were voting)
30/100 × 200 = 60
