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nika2105 [10]
4 years ago
5

Someone help ASAP serious answers only or i will report

Mathematics
1 answer:
nadezda [96]4 years ago
3 0
T represents hours, so if c(1.5)=c(t) as it mentioned in the problem, then 1.5 equals hours, and c represents cost, so if cost + time equals nine then I think it's a
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Trava [24]

Answer:

i think its the third option

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Tim is designing a logo. The logo is a polygon. Whose shape is a square attached to an equilateral triangle. The square and the
Sauron [17]
Given:
2 shapes : square and equilateral triangle
side length = 2 cm
height of equilateral triangle = 1.7 cm

Equilateral triangle means that all sides are of equal measurement.

Area of a Square = a² ⇒ (2cm)² = 4cm²
Area of an equilateral triangle = √3/4 * a² 
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Area of the logo = 4 cm² + 1.72 cm² = 5.72 cm²
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3 years ago
I will give a brainliest to who ever answers this question first!
SVEN [57.7K]
0.0000000952 in scientific notation
9.52 × 10-8
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3 years ago
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75 points. Will give certified if work is shown and the answer is correct.
Svetach [21]
Volume of the first dwarf planet (r₁ = 832 mi):

V_1=\dfrac{4}{3}\cdot\pi\cdot r_1^3=\dfrac{4}{3}\cdot\pi\cdot 832^3=\dfrac{2303721472}{3}\pi\approx7.679\cdot10^8\pi\,\text{mi}^3

Volume of the second dwarf planet (r₂ = 829 mi):

V_2=\dfrac{4}{3}\cdot\pi\cdot r_2^3=\dfrac{4}{3}\cdot\pi\cdot 829^3=\dfrac{2278891156}{3}\pi\approx7.5963\cdot10^8\pi\,\text{mi}^3

So difference between the volumes is:

V_1-V_2\approx7.679\cdot10^8\pi-7.5963\cdot10^8\pi=0.0827\cdot10^8\pi=\boxed{8270000\pi\,\text{mi}^3}

or if we want exact value (we use (a³-b³) = (a-b)(a²+ab+b²) ):

V_1-V_2=\dfrac{4}{3}\cdot\pi\cdot r_1^3-\dfrac{4}{3}\cdot\pi\cdot r_2^3=\dfrac{4}{3}\pi(r_1^3-r_2^3)=\dfrac{4}{3}\pi(832^3-829^3)=\\\\\\=\dfrac{4}{3}\pi(832-829)(832^2+832\cdot829+829^2)=\\\\\\=\dfrac{4}{3}\pi\cdot3(692224+689728+687241)=4\pi\cdot2069193=\boxed{8276772\pi\,\text{mi}^3}
3 0
3 years ago
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