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zavuch27 [327]
3 years ago
6

How would I solve this and where would I put the dots?

Mathematics
1 answer:
Maslowich3 years ago
8 0

Step-by-step explanation:

You would solve it by turning it into a equation and solving it. You would place the dots on the graph and put them in the points where they are supposed to go.

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If x varies inversely as the square of y and if x=3 when y=-1, what is the value of x when y =3
lyudmila [28]

Answer:

x would be (1/3) when y = 3.

Step-by-step explanation:

The question states that x varies "inversely" as y^2. In other words, there is a non-zero number a (a constant) such that:

\displaystyle x = \frac{a}{y^2}.

The challenging part is to find the value of a in this equation.

Given that x = 3 when y = -1, replace the x in this equation with 3 and y with (-1). This equation should still be valid:

\displaystyle 3 = \frac{a}{(-1)^{2}}.

Solve for a:

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Hence, the relation between x and y becomes:

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In other words, the value of x would be \displaystyle \frac{1}{3} when y = 3.

7 0
3 years ago
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I think that it is false
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