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marishachu [46]
3 years ago
5

At top speed, a coyote can run at a speed of 44 miles per hour. if a coyote could maintain its top speed, how far could it run i

n 15 minutes?
A- 2.93 miles
B- 11 miles
C- 176 miles
D- 660 miles
Mathematics
2 answers:
FromTheMoon [43]3 years ago
4 0
The anwser would be B -11 miles you just have to divide by 4
hjlf3 years ago
4 0

Answer:

Option B is correct

11 miles

Step-by-step explanation:

Using formula:

\text{Distance} = \text{Speed} \times \text{Time}

As per the statement:

At top speed, a coyote can run at a speed of 44 miles per hour.

⇒Speed = 44 miles per hour

It is also given that:

Time =  15 minutes

Use conversion:

1 minute = \frac{1}{60} hours

then;

15 minutes =  \frac{15}{60} =\frac{1}{4} hours

Substitute the given values in the formula we have;

\text{Distance} = 44 \times \frac{1}{4} = 11 miles

Therefore, 11 miles  could it run in 15 minutes

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Find the center and radius of the circle whose equation is x 2 + y 2 + 10x − 1
Margaret [11]

we conclude that the center of the circle is the point (-5, 0).

<h3>How to find the center of the circle equation?</h3>

The equation of a circle with a center (a, b) and a radius R is given by:

(x - a)^2 + (y - b)^2 = R^2

Here we are given the equation:

x^2 + y^2 + 10x - 1 = 0

Completing squares, we get:

x^2 + 10x + y^2 = 1

Now we can add and subtract 25 to get:

x^2 + 10x + 25 - 25 + y^2 = 1\\\\(x + 5)^2 -25 + y^2 = 1\\\\(x + 5)^2 + (y - 0)^2 = 26

Comparing that with the general circle equation, we conclude that the center of the circle is the point (-5, 0).

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3 0
2 years ago
[30 POINTS] Please help!!!
Len [333]

Answer:

Part 1) y=1.5x+5  

Part 2) y=-(2/3)x-(11/3)

Part 3) y=0.25x+2.75    

Part 4) y=-2x+5  

Part 5) y=0.5x-1  

Part 6) The graph in the attached figure

Step-by-step explanation:

Part 1) we have

m=3/2=1.5

point(-2,2)

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

substitute

y-2=1.5(x+2)

y=1.5x+3+2

y=1.5x+5

Part 2) we know that  

If two lines are perpendicular

then

the product of their slopes is equal to minus one

so

m1*m2=-1

the slope of the line 1 is equal to

m1=1.5

Find the slope m2

1.5*m2=-1

m2=-2/3

Find the equation of the line 2  

we have

m2=-2/3

point(-7,1)

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

substitute

y-1=(-2/3)(x+7)

y=-(2/3)x-(14/3)+1

y=-(2/3)x-(11/3)

Part 3) we have

m=1/4=0.25

point(1,3)  

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

substitute

y-3=0.25(x-1)

y=0.25x-0.25+3

y=0.25x+2.75

Part 4) we have

m=-2

b=5 -----> y-intercept

we know that

The equation of the line into slope intercept form is equal to

y=mx+b

substitute the values

y=-2x+5

Part 5) we have that

The slope of the line 4 is equal to -2

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the slope of the line perpendicular to the line 4 is equal to

-2*m=-1\\m=(1/2)=0.5

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m=0.5

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y-y1=m(x-x1)

substitute

y+2=0.5(x+2)

y=0.5x+1-2

y=0.5x-1

Part 6)

using a graphing tool

see the attached figure

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Andrej [43]
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n + d = 27
n + d - d =27 - d
n = 27 - d

$0.05(27-d) + $0.10(d) = $1.90
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1.35 +0.05d = $1.90
1.35 - 1.35 +0.05d = $1.90 -1.35
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n = 27 - 11
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$0.80 + $1.10 = $1.90
$1.90 = $1.90
4 0
3 years ago
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