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marishachu [46]
3 years ago
5

At top speed, a coyote can run at a speed of 44 miles per hour. if a coyote could maintain its top speed, how far could it run i

n 15 minutes?
A- 2.93 miles
B- 11 miles
C- 176 miles
D- 660 miles
Mathematics
2 answers:
FromTheMoon [43]3 years ago
4 0
The anwser would be B -11 miles you just have to divide by 4
hjlf3 years ago
4 0

Answer:

Option B is correct

11 miles

Step-by-step explanation:

Using formula:

\text{Distance} = \text{Speed} \times \text{Time}

As per the statement:

At top speed, a coyote can run at a speed of 44 miles per hour.

⇒Speed = 44 miles per hour

It is also given that:

Time =  15 minutes

Use conversion:

1 minute = \frac{1}{60} hours

then;

15 minutes =  \frac{15}{60} =\frac{1}{4} hours

Substitute the given values in the formula we have;

\text{Distance} = 44 \times \frac{1}{4} = 11 miles

Therefore, 11 miles  could it run in 15 minutes

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3 years ago
Find an equation for the sphere with center and passing through the point
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3 years ago
Melody had 45. She spent 32.75 on a blouse . Then her mother gave her 15.50. How much money does Melody have now ?
koban [17]

Answer:

Melody have now $27.75

Step-by-step explanation:

We will proceed to solve the problem in parts so that it can be better understand

so

1) Originally Melody had $45

2) She spent $32.75 on a blouse

so

In this moment Melody has --------> $45-$32.75=$12.25

3) Her mother gave her $15.50

so

In this moment Melody has --------> $12.25+$15.50=$27.75

therefore

Melody have now $27.75

5 0
2 years ago
Anyone know the answer to this algebra problem?
ikadub [295]

Answer:  \bold{a=1\qquad b=\dfrac{1}{16}\qquad c=\dfrac{1}{64}\qquad d=1\qquad e=\dfrac{4}{9}\qquad f=\dfrac{16}{81}}

<u>Step-by-step explanation:</u>

\begin{array}{c|l}\underline{\quad x\quad}&\underline{\quad 4^{-x}\qquad \qquad}\\-1&4^{-(-1)}=4^1=4\\\\0&4^{-(0)}=4^0=1\\\\2&4^{-(2)}=\dfrac{1}{4^2}=\dfrac{1}{16}\\\\4&4^{-(4)}=\dfrac{1}{4^4}=\dfrac{1}{64}\end{array}

\begin{array}{c|l}\underline{\quad \bigg x \quad}&\underline{\quad \bigg(\dfrac{2}{3}\bigg)^x\qquad \qquad}\\\\-1&\bigg(\dfrac{2}{3}\bigg)^{-1}=\dfrac{3}{2}\\\\0&\bigg(\dfrac{2}{3}\bigg)^{0}=1\\\\2&\bigg(\dfrac{2}{3}\bigg)^{2}=\dfrac{2^2}{3^2}=\dfrac{4}{9}\\\\4&\bigg(\dfrac{2}{3}\bigg)^{4}=\dfrac{2^4}{3^4}=\dfrac{16}{81}\end{array}

3 0
2 years ago
PLZZZZ HELLPPP MEEE GET ANSWER
nadya68 [22]

Answer:

<em>See above photograph</em>

Step-by-step explanation:

This is how your graph will look like with an x-intercept of [−5, 0] (will not see, according to the scale, but on my device, you can), and a y-intercept of [0, 50]. The way to figure out all the coordinates upon this scale is to simply create a y-x value chart. Plug in each input value [x-value] to get your output value [y-value]:

<u>x|y</u>

0|50

1|60

2|70

3|80

4|90

5|100

6|110

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8|130

9|140

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Then, you simply just draw your line based of this chart.

I am joyous to assist you anytime.

4 0
3 years ago
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