Answer:
The width is 50 yards and the length is 141 yards.
Step-by-step explanation:
Let's call: L the length of the field and W the width of the field.
From the sentence, the perimeter of the rectangular playing field is 382 yards we can formulate the following equation:
2L + 2W = 382
Because the perimeter of a rectangle is the sum of two times the length with two times the width.
Then, from the sentence, the length of the field is 9 yards less than triple the width, we can formulate the following equation:
L = 3W - 9
So, replacing this last equation on the first one and solving for W, we get:
2L + 2W = 382
2(3W - 9) + 2W = 382
6W -18 +2W = 382
8W - 18 = 382
8W = 382 + 18
8W = 400
W = 400/8
W = 50
Replacing W by 50 on the following equation, we get:
L = 3W - 9
L = 3(50) - 9
L = 141
So, the width of the rectangular field is 50 yards and the length is 141 yards.
Answer:
Table A
Step-by-step explanation:
looking at the two tables, we have the observations as follows;
For table B, if we divide x by y; we have a ratio of 2/3
This happens throughout the table
What this means is that x = 2/3 * y
But for table A, we notice a pattern for the first two lines
The pattern here is that x = 2y
But as we move to the next two rows, we notice this fails and thus, we fail to establish a pattern that works for all the rows;
Hence table B has a pattern for all its rows
