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Nesterboy [21]
3 years ago
14

A solution is prepared by mixing 50.0 mL of ethanol with 300.0 mL of water. What is the volume percent of ethanol in this soluti

on? Assume volumes are additive.
Chemistry
1 answer:
lora16 [44]3 years ago
3 0

Answer:

The answer to your question is 14.3 %

Explanation:

Data

volume of ethanol = 50 ml

volume of water = 300 ml

volume percent = ?

Formula

Percent by volume = (volume of solute/volume of solution) x 100

Volume of solute = 50 ml

volume of solution = 300 + 50 = 350

Substitution

Percent by volume = (50/350) x 100

Simplification and result

<u>Percent by volume = 14.3 %</u>

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Consider the first-order reaction described by the equation At a certain temperature, the rate constant for this reaction is 5.8
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