The correct equilibrium expression would be one that has products over reactants, and to the power of their stoichiometric coefficient. Also, it would not include any liquids or solids.
The equilibrium expression for your balanced reaction is:
![\Large K_c = \sf{\frac{[SO_3]^2_{equil}}{[SO_2]^2_{equil}[O_2]^2_{equil}}](https://tex.z-dn.net/?f=%5CLarge%20K_c%20%3D%20%5Csf%7B%5Cfrac%7B%5BSO_3%5D%5E2_%7Bequil%7D%7D%7B%5BSO_2%5D%5E2_%7Bequil%7D%5BO_2%5D%5E2_%7Bequil%7D%7D)
<h3>Solution:</h3>
f(x) = 3x - 1 = 0
f(x) = x = 1/3
By putting the value of x in g(x), we get
g(x) = 2(1/3)^2 - 3
g(x) = 2(1/9) - 3
g(x) = 2/9 - 3
g(x) = -25/9
<h2>Answer:</h2>
g(x) = -25/9
Answer:
It was part of a slow underwater eruption.
Explanation: Or just A (:
Answer:
When water temperature increases (right), the rate of evaporation also increases. In turn, the amount of water vapor in the "air space" above the water increases. ... But, with increased evaporation, more water molecules exist in the air above the water, which in turn increases the condensation rate.
Answer:
836.8J
Explanation:
Heat energy = ?
Mass = 100g
Initial temperature (T1) = 21°C
Final temperature (T2) = 23°C
Specific heat capacity of water (c) = 4.184J/g°C
To solve this question, we'll need to use the formula for calculating heat energy of a substance.
Q = mc∇t
Q = heat energy of substance
M = mass of substance
C = specific heat capacity of substance
∇t = change in temperature = T2 - T1
Q = 100 × 4.184 × (23 -21)
Q = 418.4 × 2
Q = 836.8J
The heat energy required to raise 100g of water from 21°C to 23°C is 836.8J
