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gogolik [260]
3 years ago
13

Based on the equation below, which of the following statements best describes what should be observed as the reaction takes plac

e?
Zn(s) + 2HCl(aq) = ZnCl2(aq) + H2(g)

Select one or more:
a. Chlorine forming a solid precipitate
b. Bubbles forming from hydrogen gas production
c. Solid zinc dissolving
d. Bubbles forming from chlorine gas production
Chemistry
1 answer:
lara [203]3 years ago
7 0
The answer is. C, solid zinc dissolving.
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The half-life of gold-198 is 2.7 days. After
Pie

Answer: 8.1 days

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant = x

a - x = amount left after decay process= \frac{x}{4} 

a) to find rate constant

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

k=\frac{0.693}{2.7days}=0.257days^{-1}

b) for completion of one fourth of reaction

t=\frac{2.303}{k}\log\frac{x}{\frac{x}{4}}

t=\frac{2.303}{0.257}\log{4}

t=8.1days

Thus after 8.1 days , one fourth of original amount will remain.

8 0
4 years ago
What would be the volume of mercury sample that has a mass of 52.757 g? The density of mercury is 12.5g / mL .
frozen [14]

Answer:

Explanation:

Divide the mass by the density and the units of grams will cancel so youll end up with mL.

(52.757g)/(12.5g/mL) = 4.2mL

5 0
3 years ago
Determine the total mass of ethanol produced when 279. Grams of glucose rescts completely to form ethanol and 132 grams of carbo
Sergio039 [100]
279 g * (1 mol/180.559g glucose) * (2 mol ethanol/1 mol glucose) * (46.068g ethanol/1mol) =

142 g ethanol produced
5 0
4 years ago
7. How much energy in KJ is released when 15.0 g of steam at 100.0 degrees Celsius is condensed and then frozen to ice at 0.0 de
Aliun [14]

Answer:

-6.27 kj

Explanation:

Given data:

Energy released = ?

Mass of steam = 15 g

Initial temperature = 100°C

Final temperature = 0°C

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of water is 4.18 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT =  0°C - 100°C = -100°C

Q = 15g × 4.18 j/g.°C  × -100°C

Q = -6270 j

J to KJ:

-6270 j/1000 = -6.27 kj

4 0
4 years ago
Mass in grams of 6.023×1023 atom of Ca​
Mademuasel [1]

Answer:

\boxed {\boxed {\sf 40.08 \ grams}}

Explanation:

First, find the molar mass of calcium (Ca). This can be found on the Periodic Table.

  • 40.08 g/mol

Next, find the number of moles.

Avogadro's Number tells us the number of atoms in one mole.

  • It is 6.023*10²³

Therefore, there are 6.023*10²³ atoms in 1 mole.

We have 6.023*10²³ atoms of calcium, so it must also be 1 mole of calcium.

Finally, find the mass. Set up a proportion using the molar mass of calcium.

1 \ mol \ Ca * \frac{40.09 \ g}{1 \ mol \ Ca}

Multiply. The moles (mol Ca) will cancel.

1 * 40.08 \ g

40.08 \ g

There are <u>40.08 grams </u>in 6.023*10²³ atoms of calcium.

5 0
3 years ago
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