Ksp=3.45×10⁻¹¹
CaF₂(s) ⇄ Ca²⁺(aq) + 2F⁻(aq)
Ksp=[Ca²⁺][F⁻]²
[Ca²⁺]=C(CaF₂)
[F⁻]=2C(CaF₂)
Ksp=4{C(CaF₂)}³
C(CaF₂)=∛(Ksp/4)
C(CaF₂)=∛(3.45×10⁻¹¹/4)=2.05×10⁻⁴ mol/L
2.05×10⁻⁴ M
The solubility of NaCl in water will not be affected by an increase in pressure.
We know that the density of NaCl(s) in 2.165 g/cm³ at 25 °C and we want to know how will its solubility in water be affected when the pressure is increased.
<h3>What is solubility?</h3>
Solubility is the maximum mass of a solute that can be dissolved in 100 grams of solvent at a determined temperature.
The solubility of a solid, such as NaCl, in a liquid, is mainly affected by the temperature. However, since solids are not compressible, an increase in pressure will not affect its solubility.
On the other hand, the solubility of gases in water will increase with an increase in pressure, as stated by Henry's law.
The solubility of NaCl in water will not be affected by an increase in pressure.
Learn more about solubility here: brainly.com/question/11963573
False
A heliocentric is when the model is
representing the sun as the center
A geocentric says the earth is at the center of the universe
There are 1000 meters in 1 Kilometer.
Hope this helps you. :)
Answer:
B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2
Explanation:
Hello,
In this case, we should understand oxidizing agents as those substances able to increase the oxidation state of another substance, therefore, in B. reaction we notice that copper oxidation state at the beginning is zero (no bonds are formed) and once it reacts with nitric acid, its oxidation states raises to +2 in copper (II) nitrate, thus, in B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2 nitritc acid is acting as the oxidizing agent.
Moreover, in the other reactions, copper (A.), sodium (C. and D.) remain with the same initial oxidation state, +2 and +1 respectively.
Regards.
