145. u take 180 subtract 35. It will gives u 145
Answer:
Sabemos que:
y tenemos que:
Con esto podemos encontrar el valor de a:
8*a/(a+ 4) = 6
8*a = 6*(a + 4) = 6*a + 24
8a - 6a = 24
2a = 24
a = 24/2 = 12.
Tambien sabemos que:
Y de ahí podemos despejar b:
(16*b)/(b + 8) = 12
16*b = 12*(b + 8) = 12b + 96
16b - 12b = 96
4b = 96
b = 96/4 = 24
Entonces tenemos a = 12 y b = 24, y el MH de a y b es:
MH(12,24) = 2*12*24/(12 + 24) = 24*24/36 = 16
Answer:
Step-by-step explanation:
Let's set up a proportion using the following setup.
We know 30 buses can carry 1,500 people.
We don't know how many people 5 buses can carry, so we say 5 buses carry x people.
Cross multiply. Multiply the numerator of the first fraction by the second fraction's denominator. Then, multiply the first denominator by the second numerator.
Solve for x. It is being multiplied by 30. The inverse of multiplication is division. Divide both sides by 30.
5 buses can carry 250 people.
Answer:
v ≥ -17
Step-by-step explanation:
-82 ≤ 5v + 3
-82 - 3 ≤ 5v
5v ≥ -85
v ≥ -17
Answer:
- object is moving to the right with constant speed
- object is moving to the left with constant speed
- object was stationary for a while, then started moving to the right with constant speed
Step-by-step explanation:
These graphs are of position, so the slope of the graph is the change of position with time, which is velocity. When the slope is positive, the velocity is positive, meaning its direction is to the right. When the slope is negative, the velocity is negative, meaning its direction is to the left.
When the slope is zero, the object is stationary (not moving). The position remains as it was.
1. The position vs. time curve is a straight line with positive slope. The object is moving to the right with constant velocity.
__
2. The position vs. time curve is a straight line with negative slope. The object is moving to the left with constant velocity.
__
3. The position vs. time curve is flat for a while, then increasing with constant slope. The object stayed where it was for a while, then began moving to the right (to larger values of x) with constant velocity.
