From the graph, we can see that the graph has bumps on (0,25) and (5.1, -7) coordinates.
The higher point is (0,25) and lower one is at (5.1, -7).
We need to find to find the interval of the local minimum and value of local minimum.
<em>From the graph, we can see that graph has local minimum is -7 in the interval [4,7].</em>
Therefore, correct option is 4th option.
<h3>Over the interval [4,7], the local minimum is -7.</h3>
It means to multiply those numbers. The answer is the first one.
(Look at image)
Option 1! If you expand the bracket and simplify.
Answer:
2
Step-by-step explanation:
<u>Given AP where:</u>
<u>To find</u>
<u>Since</u>
- a₄ = a₁ + 3d
- a₂ = a₁ + d
- a₆ = a₁ + 5d
<u>Initial equations will change as:</u>
- a₁ + 3d = 2(a₁ + d) - 1 ⇒ a₁ + 3d = 2a₁ + 2d - 1 ⇒ a₁ = d + 1
- a₁ + 5d = 7 ⇒ a₁ = 7 - 5d
<u>Comparing the above:</u>
- d + 1 = 7 - 5d
- 6d = 6
- d = 1
<u>Then:</u>
- a₁ = d + 1 = 1 + 1 = 2
- a₁ = 2
The first term is 2
Given:
Angle A is 4 degrees greater than the measure of Angle B. Both angles are complementary
Complementary angles have a sum of 90°
Angle A = x + 4° ; Angle B = x
x + 4° + x = 90°
2x = 90° - 4°
2x = 86°
x = 86° ÷ 2
x = 43° ANGLE B.
Angle A = x + 4° ⇒ 43° + 4 = 47°
Given:
Angle D is 5 times the measure of Angle E. These angles are supplementary. This means that their sum is 180°
Angle D = 5x ; Angle E = x
5x + x = 180°
6x = 180°
x = 180° ÷ 6
x = 30° Angle E.
Angle D = 5x = 5(30) = 150°
