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gavmur [86]
2 years ago
11

I did my best to fit it all lol, can someone please help? <3

Mathematics
2 answers:
Ivenika [448]2 years ago
7 0

Answer:

8a: 0 8b: -1/3

Step-by-step explanation:

slope is y2-y1/x2-x1

8a: 8+12/0=0

8b: 1+2/-3-6=3/-9=-1/3

pav-90 [236]2 years ago
3 0

Answer:

8a. 0 8b. -1/3

Step-by-step explanation:

slope formula: \frac{y_{2} - y_{1}}{x_{2} - x{1}}

8a. => (8 + 12)/(17 - 17) = 20/0 = 0

8b. (1 + 2)/(-3 - 6) = 3/-9 = - 1/3

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bonufazy [111]
15$ is the answer to this question.
7 0
2 years ago
¿Cuál de los siguientes puntos no pertenece a la función cuadrática f(x) = 1-x^2 ?
dusya [7]

Answer:

<h2>A. (0,1)</h2>

Step-by-step explanation:

The question lacks the e=required option. Find the complete question below with options.

Which of the following points does not belong to the quadratic function

f(x) = 1-x²?

a.(0,1) b.(1,0) c.(-1,0)

Let f(x) = 0

The equation becomes 1-x² = 0

Solving 1-x² = 0 for x;

subtract 1 from both sides;

1-x²-1 = 0-1

-x² = -1

multiply both sides by minus sign

-(-x²) = -(-1)

x² = 1

take square root of both sides;

√x² = ±√1

x = ±1

x = 1 and x = -1

when x = 1

f(x) = y = 1-1²

y = 1-1

y = 0

when x = -1

f(x) = y = 1-(-1)²

y = 1-1

y = 0

Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)

3 0
3 years ago
PLEASE HELP 25 POINTS<br> Evaluate 4(3 - 1)^2<br> O A. 16<br> O B. 128<br> O C. 64<br> O D. 32
balandron [24]
The answer is 16 bc yeah i said it was
6 0
3 years ago
Solve each equation by substitution:<br><br>y = 6x - 17<br>y= -4x +23​
NISA [10]

Answer:

y = 6x - 17 \\ y =  - 4x + 23 \\ then \\ 6 x - 17 =  - 4x + 23 \\ 10x = 40 \\ x = 4 \\ y = 7

7 0
2 years ago
Here ya go take some free points . :)
horrorfan [7]

Answer:

Is there anything I can help with though?

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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