I did my best to fit it all lol, can someone please help? <3
2 answers:
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A) 4a - 3b + 2c
4(2, -1, 5) - 3(4, 3 , -2) + 2(5, 4, 0) = (8, -4, 20) - (12, 9, - 6) + (10, 8, 0) =
= (8 - 12 + 10 , -4 - 9 + 8 , 20 + 6 + 0) = (6, - 5, 26)
Answer: (6, - 5, 26)
b) magnitude of vector b
c) vector of length 7 parallel to vector c
=> m(5,4,0) = (5m,4m,0)
=>
=> m = 7 / √41 ≈ 1.093
=> 1.093 (5, 4, 0) = (5.465 , 4.372, 0)
Answer: (5.465 , 4.372 , 0)
4(2, -1, 5) - 3(4, 3 , -2) + 2(5, 4, 0) = (8, -4, 20) - (12, 9, - 6) + (10, 8, 0) =
= (8 - 12 + 10 , -4 - 9 + 8 , 20 + 6 + 0) = (6, - 5, 26)
Answer: (6, - 5, 26)
b) magnitude of vector b
c) vector of length 7 parallel to vector c
=> m(5,4,0) = (5m,4m,0)
=>
=> m = 7 / √41 ≈ 1.093
=> 1.093 (5, 4, 0) = (5.465 , 4.372, 0)
Answer: (5.465 , 4.372 , 0)
Answer:
Yes, Cora is correct.
The equation of line with point (2,6) and slope of line (-1/3)
is x + 3y - 20 = 0
Step-by-step explanation:
Yes, the equation of a line can be written using a point and a slope of the line equation.
Cora has used the POINT SLOPE FORMULA, to represent the line equation.
In <u>Point Slope formula</u>:
The equation with slope m and points (x0,y0) can be written as:
(y-y0) =m (x-x0)
Here, the point (x0,y0) = (2,6)
and slope m = (-1/3)
So, the equation can be written as:
Hence, the equation of line with point (2,6) and slope of line (-1/3)
is x + 3y - 20 = 0