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3 years ago

Plzzzzz help me plzzzz le may give brainlist

Mathematics

1 answer:

gladu [14]3 years ago

6 0

Answer:

b. Multiply 15 by 9, then divide by 2

Step-by-step explanation:

15 / 2/9 = 15 * 9/2

Answer: b. Multiply 15 by 9, then divide by 2

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Extreme cold and hot temperatures are known to affect the operation of electronic components. Winter is approaching and you are

Musya8 [376]

Answer:

A 95% confidence interval for the true mean minimum temperature that will damage an iPod is between 2.55°F and 7.45°F

Test statistic(Z) = 2.31

P-value = 0.0104

Step-by-step explanation:

Step 1

Null hypothesis: The average damaging temperature of nine iPods is 5°F

Alternate hypothesis: The average damaging temperature of nine iPods differs from 5°F

Step 2

Mean=5°F, Sd=3, df=n-1=9-1=8

The t-value corresponding to 8 degrees of freedom and 95% confidence level (5% significance level) is 2.306

Confidence Interval(CI) = (mean + or - t×sd/√n)

CI = (5 + 2.306×3/√8) = 5 + 6.918/2.828= 5+2.45=7.45°F

CI = (5 - 2.306×3/√8) = 5-2.45 = 2.55°F

Z = (sample mean - population mean)/(sd÷√n) = (5-2.55)/(3÷√8) = 2.45/1.061 = 2.31

Step 3

Using the standard distribution table, the cumulative area to the left of Z = 2.31 is 0.9896

P-value = 1 - 0.9896 = 0.0104

Step 4

Conclusion: A 95% confidence interval for the true mean minimum temperature that will damage an iPod is between 2.55°F and 7.45°F

7 0

3 years ago

Help mayyy pleaseee and tyy

Kay [80]

Answer:

2x=-7y not sure tho just guessping probably wrong sorry

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Which box plot correctly displays the data set with a maximum of 48, a minimum of 27, a median of 36, an upper quartile of 45, a

Vitek1552 [10]

Answer:

Image 1

Step-by-step explanation:

To answer this question, we need to know how to use a box plot.

I've attached an image that demonstrates this well and can teach you what each part of the box plot means.

Specifically, the 2 farthest dots at the end are the minimum and maximum. The two sides where the box starts are the lower and upper quartiles. Finally, the line in the middle of the box is the median.

With this, we can analyze each box plot and determine which one is correct.

Box Plot 1: Everything is plotted correctly- Maximum and minimum plotted correctly, median plotted correctly, upper and lower quartile plotted correctly.

Box Plot 2: Everything plotted correctly EXCEPT maximum of 48 is represented at 46.

Box Plot 3: Everything plotted correctly EXCEPT the upper quartile of 45 is at 39.

Box Plot 4: Upper quartile represented at 39 and maximum represented at 46 are both incorrect.

4 0

2 years ago

An article includes the accompanying data on compression strength (lb) for a sample of 12-oz aluminum cans filled with strawberr

seraphim [82]

Answer:

Step-by-step explanation:

This is a test of 2 independent groups. The population standard deviations are not known. Let μ1 be the mean compression strength from the extra carbonation of strawberry drink and μ2 be the mean compression strength from the extra carbonation of cola.

The random variable is μ1 - μ2 = difference in the mean compression strength from the extra carbonation of strawberry drink and the mean compression strength from the extra carbonation of cola.

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 < μ2 H1 : μ1 - μ2 < 0

This is a left tailed test.

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

From the information given,

x1 = 530

x2 = 553

s1 = 23

s2 = 16

n1 = 10

n2 = 10

t = (530 - 533)/√(23²/10 + 16²/10)

t = - 2.6

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [23²/10 + 16²/10]²/[(1/10 - 1)(23²/10)² + (1/10 - 1)(16²/10)²] = 6162.25/383.752

df = 16

We would determine the probability value from the t test calculator. It becomes

p value = 0.0097

Since alpha, 0.05 > than the p value, 0.0097, then we would reject the null hypothesis. Therefore, at 5% significance level, the data suggests that the extra carbonation of cola results in a higher average compression strength.

4 0

3 years ago

10) Will mark BRAINLIEST + 10 POINTS :)

Mariana [72]

Answer is A.

√6 + √2
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4

4 0

3 years ago

Read 2 more answers