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lozanna [386]
3 years ago
10

The diameter of a circle is 36 centimeters. Find the radius

Mathematics
1 answer:
olga2289 [7]3 years ago
6 0

Answer:

Given

in a circle

Diameter ( d) = 36 cm

Then we have the formula that

Radius (r) = d / 2

= 36 / 2 = 18 cm

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I need help on this question
Alenkinab [10]

Answer:

B. 63 degrees

Step-by-step explanation:

Its the same angle as the one above it.

I hope this helps :)

Have a nice day!

8 0
3 years ago
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What is the area of this shape?
m_a_m_a [10]

Step-by-step explanation:

idk the answer but find the area of a circle with the radius of 45 m and then find the area of the rectangle then add them together.

5 0
3 years ago
Please Show Work 6x(-4) Six times negative four.
Ainat [17]

Answer:

6 x (-4)

= (-24)

Step-by-step explanation:

when multiplying integers, you first need to multiply the numbers. Then you need to look at the signs if both numbers have the same signs or if it doesn't. if the signs are the same, the product is a positive . If the two numbers have different signs, you will get a negative product.

NOTE: if a number doesn't have a sign, it's a positive number

7 0
3 years ago
Si un rectángulo con perímetro de 74 pulgadas tiene un largo de 5 pies más que el ancho,
baherus [9]

Perímetro del rectángulo = 74 pulgadas

Deje que el ancho del rectángulo sea 'x'.

Entonces, la longitud de este rectángulo = x + 5

We know that :

\color{hotpink}\tt \: Perímetro  \: del \:  rectángulo =\color{plum} 2 × (l + b)

Lo que significa :

=\tt 2(x + x + 5) = 74

=\tt 2(2x + 5) = 74

=\tt 4x +10 = 74

=\tt 4x = 74 - 10

=\tt 4x = 64

=\tt x =  \frac{64}{4}

\color{plum} =\tt x = 16

Por lo tanto, el ancho de este rectángulo = 16 pulgadas

Entonces, la longitud de este rectángulo :

=\tt x + 5

= \tt16 + 5

\color{plum} =\tt 21 \: pulgadas

La longitud de este rectángulo = 21 pulgadas

<h2>Por lo tanto :</h2>

● Longitud del rectángulo = <em>21 pulgadas</em>

● Ancho del rectángulo = <em>16 pulgadas</em>

3 0
3 years ago
3. Which of the following quadratic equations has no solution? A) 0 = −2(x − 5)2 + 3 B) 0 = −2(x − 5)(x + 3) C) 0 = 2(x − 5)2 +
klemol [59]

Answer:

D) 0 = 2(x + 5)(x + 3)

Step-by-step explanation:

Which of the following quadratic equations has no solution?

We have to solve the Quadratic equation for all the options in other to get a positive value as a solution for x.

A) 0 = −2(x − 5)2 + 3

0 = -2(x - 5) × 5

0 = (-2x + 10) × 5

0 = -10x + 50

10x = 50

x = 50/10

x = 5

Option A has a solution of 5

B) 0 = −2(x − 5)(x + 3)

Take each of the factors and equate them to zero

-2 = 0

= 0

x - 5 = 0

x = 5

x + 3 = 0

x = -3

Option B has a solution by one of its factors as a positive value of 5

C) 0 = 2(x − 5)2 + 3

0 = 2(x - 5) × 5

0 = (2x -10) × 5

0 = 10x -50

-10x = -50

x = -50/-10

x = 5

Option C has a solution of 5

D) 0 = 2(x + 5)(x + 3)

Take each of the factors and equate to zero

0 = 2

= 0

x + 5 = 0

x = -5

x + 3 = 0

x = -3

For option D, all the values of x are 0, or negative values of -5 and -3.

Therefore the Quadratic Equation for option D has no solution.

3 0
3 years ago
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