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3 years ago

Find the values of a b and c for which the quadratic equation ax^2+bx+c=0 has the solutions -3 and 1

1 answer:

7 0

It may be easier to start from

.. a(x +3)(x -1) = 0
.. a(x^2 +2x -3) = 0

The quadratic
.. ax^2 +bx +c = 0 will have solutions -3 and 1 for ...

.. a ≠ 0
.. b = 2a
.. c = -3a

You might be interested in

the ordered pairs (0,-1),(1,0),(2,3),(3,8),(4,15) represent a function what is a rule that represents this function? Please help

yarga [219]

Answer:

The function rule is

$f: x\to \: {x}^{2} - 1$

Step-by-step explanation:

The given ordered pairs are (0,-1), (1,0),(2,3),(3,8),(4,15)

We can observe the following pattern.

$f(0) = {0}^{2} - 1 = - 1$

$f(1) = {1}^{2} - 1 = 0$

$f(2) = {2}^{2} - 1 = 3$

$f(3) = {3}^{2} - 1 = 8$

$f(4) = {4}^{2} - 1 = 15$

When we generalize this pattern, we obtain:

$f(x) = {x}^{2} - 1$

This is the function equation.

The function rule is

$f: x\to \: {x}^{2} - 1$

8 0

3 years ago

What is the common ratio for the geometric sequence?<br><br> 35/2, 7, 14/5, 28/25, ..…

LiRa [457]

Answer:

2/5

Step-by-step explanation:

8 0

3 years ago

If a university wants to maintain a 14:1 ratio between students and teachers, how many teachers would be needed to accommodate 8

kolezko [41]

The answer is C. 64 teachers.

14 x 64= 896
so 1 x 64= 64

4 0

3 years ago

Read 2 more answers

A pack of condtruction paper is 0.6 cm thick. If there are 24 sheets in the pack,how thick is each sheet? PLEASE SHOW WORK

Anuta_ua [19.1K]

Divide 0.6 by 24. The answer is 0.025

7 0

4 years ago

Y=x^2-6x-16 in vertex form

satela [25.4K]

Answer:

$y=(x-3)^{2} -25$

Step-by-step explanation:

The standard form of a quadratic equation is $y=ax^{2} +bx+c$

The vertex form of a quadratic equation is $y=a(x-h)^{2} +k$

The vertex of a quadratic is (h,k) which is the maximum or minimum of a quadratic equation. To find the vertex of a quadratic, you can either graph the function and find the vertex, or you can find it algebraically.

To find the h-value of the vertex, you use the following equation:

$h=\frac{-b}{2a}$

In this case, our quadratic equation is $y=x^{2} -6x-16$ . Our a-value is 1, our b-value is -6, and our c-value is -16. We will only be using the a and b values. To find the h-value, we will plug in these values into the equation shown below.

$h=\frac{-b}{2a}$ ⇒ $h=\frac{-(-6)}{2(1)}=\frac{6}{2} =3$

Now, that we found our h-value, we need to find our k-value. To find the k-value, you plug in the h-value we found into the given quadratic equation which in this case is $y=x^{2} -6x-16$

$y=x^{2} -6x-16$ ⇒ $y=(3)^{2} -6(3)-16$ ⇒ $y=9-18-16$ ⇒ $y=-25$

This y-value that we just found is our k-value.

Next, we are going to set up our equation in vertex form. As a reminder, vertex form is: $y=a(x-h)^{2} +k$

a: 1

h: 3

k: -25

$y=(x-3)^{2} -25$

Hope this helps!

3 0

3 years ago