The closer Diana gets to the building, the smaller the angle becomes
Diana is 17.6 feet closer to the building
<h3>How to calculate the distance from the building</h3>
To calculate the distance between her and the building, we make use of the following tangent ratio
Where:
- h represents the height of the building; h = 130
- d represents the distance from the building
So, we have:
Make d the subject
Evaluate tan(40)
Initially, Diana is at a distance of 172.53.
The difference in both distance is:
Hence, Diana is 17.6 feet closer to the building
Read more about trigonometry ratios at:
brainly.com/question/4326804
Answer:
804 in^2
Step-by-step explanation:
The surface area of a sphere is given by A = 4πr^2, where r is the radius of the sphere.
Here, A = 4π*8^2 in^2 (must use units of measurement)
=256π in^2, or approximately 804 in^2
If we assume this is a right triangle
for a right triangle
if it has legs length a and b and hyptonouse c then
a²+b²=c²
given
a leg is 24
hyptonuse =25
the other leg is b
24²+b²=25²
576+b²=625
minus 576 from both sides
b²=49
sqrt both sides
b=7
the other leg is 7 units
For this case we have the following function:
n (t) = 2400 * (5) ^ t
For n (t) = 60000 we have:
60000 = 2400 * (5) ^ t
We clear the value of t.
For this we use the logarithm:
(5) ^ t = 60000/2400
log5 ((5) ^ t) = log5 (60000/2400)
t = log5 (60000/2400)
t = 2 days
Answer:
the number of bacteria in the culture will be 60 comma 000 after:
t = 2 days
Answer:
See below.
Step-by-step explanation:
This is how you prove it.
<B and <F are given as congruent.
This is 1 pair of congruent angles for triangles ABC and GFE.
<DEC and <DCE are given as congruent.
Using vertical angles and substitution of transitivity of congruence of angles, show that angles ACB and GEF are congruent.
This is 1 pair of congruent angles for triangles ABC and GFE.
Now you need another side to do either AAS or ASA.
Look at triangle DCE. Using the fact that angles DEC and DCE are congruent, opposite sides are congruent, so segments DC and DE are congruent. You are told segments DF and BD are congruent. Using segment addition postulate and substitution, show that segments CB and EF are congruent.
Now you have 1 pair of included sides congruent ABC and GFE.
Now using ASA, you prove triangles ABC and GFE congruent.
