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serious [3.7K]
3 years ago
6

What is the answer please ??!

Mathematics
2 answers:
Ainat [17]3 years ago
3 0
The correct answer is the second option down, s = \sqrt[3]{V}.

This is because in order to get the variable s by itself (solve for the variable s), we have to perform the inverse operation of cubing the variable, which would be taking the cube root of the variable. This is similar to the way that you divide when you are trying to undo multiplication when solving simple equations.

Hope this helps!
sdas [7]3 years ago
3 0
The correct answer is B. ∛V

Because V = 512   and   8³ = 512    Therefore ∛512 = 8
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Approx. 5.3 miles

Step-by-step explanation:

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3 years ago
Please help me with this
lys-0071 [83]

Answer:

0.6

Step-by-step explanation:

We know that there are 5 counters in total. 3 white and 2 black.

So we know that 3 out of 5 are white and 2 out of 5 are black.

Therefore the chance to get white is 3/5. And for black: 2/5.

We can turn these into decimals, 3/5 = 0.6 (You can make it 6/10 to make it easier.)

And 2/5 = 0.4 (You can make it 4/10 to make it easier.)

Answering the question, you should put your cross/marker on 0.6

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3 years ago
Read 2 more answers
Add 7 x 10−6 and 2.1 x 10−5.<br><br> 9.1 x 10−6<br> 2.8 x 10−6<br> 9.1 x 10−5<br> 2.8 x 10−5
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The answer is 2.8 x 10-5
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2 years ago
Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best po
Brrunno [24]

Answer: (0.63, 7.07)

Step-by-step explanation:

The confidence interval for population proportion is given by :-

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

Given :\hat{p} =0.7 ;  n=110

Significance level : 1-0.90=0.1

Critical value :  z_{\alpha/2}=1.645

Now, a 90% confidence interval for population proportion will be :-

0.7\pm (1.645)\sqrt{\dfrac{0.7(1-0.7)}{110}}\\\\\approx0.7\pm0.07\\\\=(0.7-0.07,0.7+0.07)=(0.63,\ 7.07)

Hence, a 90% confidence interval for population proportion = (0.63, 7.07)

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3 years ago
Big ideas math: modeling real life. Grade 6.
Vera_Pavlovna [14]

Answer:

Where's the question?

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3 years ago
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