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3 years ago

Simplify the ratio of 37:14

Mathematics

2 answers:

topjm [15]3 years ago

3 0

Answer:

37:14 is the simplest form of ratio. It can't be more simplified.

Step-by-step explanation:

kobusy [5.1K]3 years ago

3 0

Answer:

37:14

Step-by-step explanation:

Here we will simplify the ratio 37:14 for you and show you how we did it.

To simplify the ratio 37:14, we find the greatest common divisor of 37 and 14, and then we divide 37 and 14 by the greatest common divisor.

The greatest common divisor that you can use to simplify 37:14 is 1. Which means the answer to ratio 37:14 simplified is:

The ratio 37:14 is not the only ratio we can simplify. Enter another ratio here for us to simplify.

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3 years ago

Read 2 more answers

Hello pls help I'm dumb thx it's pre calc

Bumek [7]

(f-g)(x)=f(x)-g(x)=
$\frac{2x+6}{3x}-\frac{\sqrt{x}-8}{3x}=$
$\frac{2x+6-(\sqrt{x}-8)}{3x}=$
$\frac{2x+6-\sqrt{x}+8}{3x}=$
$\frac{2x-\sqrt{x}+14}{3x}$
answer is A

3 0

3 years ago

A farmer has a field in the shape of a triangle. The farmer has asked the manufacturing class at your school to build a metal fe

Finger [1]

Answer:

Fencing required = 1586 m

Step-by-step explanation:

The given statements can be thought of a triangle $\triangle ABC$ as shown in the diagram attached.

A be the 1st vertex, B be the 2nd vertex and C be the 3rd vertex.

Distance between 1st and 2nd vertex, AB = 435 m

Distance between 2nd and 3rd vertex, AC = 656 m

$\angle A =49^\circ$

To find:

Fencing required for the triangular field.

Solution:

Here, we know two sides of a triangle and the angle between them.

To find the fencing or perimeter of the triangle, we need the third side.

Let us use Cosine Rule to find the third side.

Formula for cosine rule:

$cos A = \dfrac{b^{2}+c^{2}-a^{2}}{2bc}$

Where

a is the side opposite to $\angle A$

b is the side opposite to $\angle B$

c is the side opposite to $\angle C$

$\Rightarrow cos 49^\circ = \dfrac{656^{2}+435^{2}-BC^{2}}{2\times 435\times 656}\\\Rightarrow BC^2 = 430336+189225-2 (435)(656)cos49^\circ\\\Rightarrow BC^2 = 430336+189225-570720\times cos49^\circ\\\Rightarrow BC^2 =619561-570720\times cos49^\circ\\\Rightarrow BC \approx 495\ m$