A is the answer because I did befor
Answer:
The choice 210
Step-by-step explanation:
![3{[3(9 - 2)] +[7(8 - 1)] }\\ 3[3(7) + 7(7)] \\ 3[21 + 49] \\ 3[70] \\ = 210](https://tex.z-dn.net/?f=3%7B%5B3%289%20-%202%29%5D%20%2B%5B7%288%20-%201%29%5D%20%7D%5C%5C%203%5B3%287%29%20%2B%207%287%29%5D%20%5C%5C%203%5B21%20%2B%2049%5D%20%5C%5C%203%5B70%5D%20%5C%5C%20%20%3D%20210)
I hope I helped you^_^
8+0.75x=25
0.75x=25(-8)
0.75x=17
17/0.75= 22.666
He can ride a total of 22 rides
To solve this we are going to use the speed equation:

where

is speed

is distance

time
We know from our problem that the upstream trip takes 2 hours, so

. We also know that the downstream trip takes 1.7 hours, so

. Notice that the distance of both trips is the same, so we are going to use

to represent that distance.
Now, lets use our equation to relate the quantities:
For the upstream trip:


equation (1)
For the downstream trip:


equation (2)
We know that the boat travels 2.5 miles per hour faster downstream, so the speed of the boat upstream will be the speed of the boat downstream minus 2.5 miles per hour:

equation (3)
Replacing (3) in (1):


equation (4)
Solving for

in equation (2):


equation (5)
Replacing (5) in (4):







equation (6)
Replacing (6) in (5)



miles
We can conclude that the boat travel

, which is approximately 28.3 miles, in one way.
Answer:
Step-by-step explanation:
1) 3 x 20 = 60 (that how much she give)
2) 60- 57.32 = 2.68 (that the change they will split up)
3) 2.68/2=1.34 ( they will each get $1.34)