Your answer is 38 I hope its correct :)
The equation of a straight like in the from y – y1 =m(x-x1) where m is the slope of the like and (x1 , y1) are the coordinates of a given point on the line — compare slope intercept form.
Answer:
see explanation
Step-by-step explanation:
A quadratic function in standard form is
y = ax² + bx + c (a ≠ 0 )
Given
y = - 3x² + 6x + 17 ← compare coefficients with standard form, then
a = - 3, b = 6, c = 17
Given the quadratic in standard form the the equation of the axis of symmetry is
x = -
= -
= 1
Equation of axis of symmetry is x = 1
4qr+20g-11q hopefully this would help you
P+o-wt=4b
-wt=4b-p-o
t=(4b-p-o)/-w
mark as brainliest if it’s helpful