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Nookie1986 [14]
3 years ago
12

CAN ANYONE HELP ME PLS.I TRIED IT OVER 4 Times

Mathematics
2 answers:
ivanzaharov [21]3 years ago
8 0

Answer:

72 in^3

Step-by-step explanation:

So to find the volume of a rectangular prism, do L * W * H for the volume. The length of the tissue box is 8, the width is 3 and the height is also 3. With this, plug these together into the equation for the volume.

8 * 3 * 3

24 * 3

72 in^3

It is cubed (^3) , since it is about finding how much space there is in a 3D object. When it is a 2D object such as a rectangle, it is instead squared (^2).

AlekseyPX3 years ago
6 0
72cubic inches

explanation:
volume of rectangle = l*w*h
8*3*3 = 72


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tresset_1 [31]
0.0000213, that should be it.
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4 years ago
nika is making cakes for a bake sale at school when she realizes she is running out of milk, each cake requires 1/4 cups of milk
Reil [10]

Answer:

Nika can make 15 cups of milk.

Step-by-step explanation:

To find how many cups she can make, we divide 3 3/4 by 1/4. First, we convert 3 3/4 to an improper fraction.

3 ¾ / ¼           Equation

15/4 /  ¼         Convert to improper

15/4 * 4/1        Reverse sign & second fraction

= 60/4

= 15

Also, 15 * 1/4 = 3  ¾, so its correct!

3 0
3 years ago
Enter the appropriate value to answer the question or solve the problem.
Stolb23 [73]

Answer:

x = 40 degrees

Step-by-step explanation:

Triangle angle sum is 180 so 180 = 65 + 75 + x.

180 = 65 + 75 + x

180 = 140 + x

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6 0
3 years ago
On a cold day, hailstones fall with a velocity of 2i − 6k m s−1 . If a cyclist travels through the hail at 10i m s−1 , what is t
Paraphin [41]

Answer:

The velocity of the hail relative to the cyclist is V_{hc}=-8\hat{i}-6\hat{k}

The angle at which hailstones falling relative to the cyclist is \theta = 36.86^\circ

Step-by-step explanation:

Given : On a cold day, hailstones fall with a velocity of 2\hat{i}-6\hat{k}\text{ m/s} . If a cyclist travels through the hail at 10\hat{i} \text{ m/s}.

To find : What is the velocity of the hail relative to the cyclist and At what angle are the hailstones falling relative to the cyclist?

Solution :

The velocity of the hailstone falls is V_h=2\hat{i}-6\hat{k}\text{ m/s}

The velocity of the cyclist travels through the hail is V_c=10\hat{i} \text{ m/s}

The velocity of the hail relative to the cyclist is given by,

V_{hc}=V_h-V_c

Substitute the value in the formula,

V_{hc}=2\hat{i}-6\hat{k}-10\hat{i}

V_{hc}=-8\hat{i}-6\hat{k}

So, The velocity of the hail relative to the cyclist is V_{hc}=-8\hat{i}-6\hat{k}

Now, The angle of hails falling relative to the cyclist is given by

\theta = \tan^{-1}(\frac{-6}{-8})

\theta = \tan^{-1}(\frac{3}{4})

\theta = 36.86^\circ

So, The angle at which hailstones falling relative to the cyclist is  \theta = 36.86^\circ

4 0
4 years ago
Solve for x:<br> 4x/5=20
alexdok [17]
The correct response is X=25
3 0
3 years ago
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