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Brut [27]
3 years ago
11

58.5g of sodium iodine are dissolved in 0.5 dm3. What concerntration would this be?

Chemistry
1 answer:
Elenna [48]3 years ago
4 0
Take 58.5 and divide that by 0.5, we get 117 grams of Sodium Iodide per liter
If you are looking for molarity. Then there are 149.88 grams in one mole of Sodium Iodide. We have 0.78 moles of sodium iodide. Divide that by 0.5 liters (also dm3)
0.78 / 0.5 = 1.56 M
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After boiling a chicken in a stock pot, you let the chicken stock cool down and place it
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Chicken fat is in the shallowest area because, being hydrophobic and lipid content of chicken, it is the lowest density compound in the broth, therefore it rises and does not precipitate. All fats usually float in liquid media because their density is less than that of water.

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For each of the following solutions, calculate [OH- ] from [H3O + ] or [H3O + ] from [OH- ]. Classify each solution as acidic, b
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The case is acidic since calculated pH is below 7 that is 2.3

The hydroxide and hydrogen ion levels in a solution are the sources for calculating pOH and pH levels, respectively, and are the basis of whether a solution is acidic or basic

[H₃O+]=5.3×10⁻³M

To determine the hydroxide ion concentration, we use:

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We isolate the hydroxide ion concentration:

[OH−]=1×10−145.3×10⁻³M

Solving this, we obtain:

[OH−]=1.9×10−¹²M

We can determine whether the solution is acidic or basic by calculating the pH level:

pH=−log[H3O+]

We substitute in the hydronium ion concentration given:

pH=−Log(5.3×10−3)pH=2.3

Since the pH is below 7, the solution is acidic

Learn more about hydroxide ion here-

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