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3 years ago

Does anyone know how to answer this or what the answer is? My sister is having a hard time figuring this out with her tutor?

Chemistry

1 answer:

ira [324]3 years ago

8 0

Its number four.Hope that helps feel free to ask me questions:)

Brainliest??

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A water bath in a physical chemistry lab is 1.85m long, 0.810m wide and 0.740m deep. If it is filled to within 2.57 in from the

jenyasd209 [6]

Answer:

The volume of water in water bath is 1,011 Liters.

Explanation:

Length of the water bath, L = 1.85 m

Width of the water bath, W= 0.810 m

Height of the water bath ,H= 0.740 m

Height of the water in water bath, h= 0.740 m - 2.57 inches

1 m = 39.37 inch

$= 0.740 m - \frac{2.57}{39.37} m = 0.6747 m$

Volume of the water in bath = L × W × h

$=1.85 m\times 0.810 m\times 0.6747 m=1.011 m^3$

$1 m^3=1000 L$

$1.011 m^3=1.011\times 1000 L=1,011 L$

The volume of water in water bath is 1,011 Liters.

6 0

4 years ago

A particular sample of pantothenic acid, a B vitamin, gives off 72.6 mL of nitrogen gas at 23 degrees c and 795 torr. What is th

disa [49]

Answer:

70.04 mL.

Explanation:

We can use the general law of ideal gas: V = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n is constant, and have two different values of V, P and T:

P₁V₁T₂ = P₂V₂T₁

P₁ = 795 torr, V₁ = 72.6 mL, T₁ = 23.0 °C + 273 = 296 K.

P₂ = 760 torr (standard pressure = 1 atm = 760 torr), V₂ = ??? mL,T₂ = 0.0 °C + 273 = 273 K (standard T).

∴ V₂ = P₁V₁T₂/P₂T₁ = (795 torr)(72.6 mL)(273 K)/(760 torr)(296 K) = 70.04 mL.

4 0

4 years ago

What do potatoes, wood, and lobster shells have in common?

STatiana [176]

They are all biotic factors, meaning they were once alive or were alive. (an abiotic factor is something that has never lived.) hope this helped.

5 0

3 years ago

What is the total number of valence electrons for cesium??

GuDViN [60]

It's an alkali metal so one, they sit on the very first of the column in the periodic table :DDDD

5 0

3 years ago

Calculate the pH of each solution at 25∘C

JulijaS [17]

Answer: pH of HCl =5, HNO3 = 1,

NaOH = 9, KOH = 12

Explanation:

pH = -log [H+ ]

1. 1.0 x 10^-5 M HCl

pH = - log (1.0 x 10^-5)

= 5 - log 1 = 5

2. 0.1 M HNO3

pH = - log (1.0 x 10 ^ -1)

pH = 1 - log 1 = 1

3. 1.0 x 10^-5 NaOH

pOH = - log (1.0 x 10^-5)

pOH = 5 - log 1 = 5

pH + pOH = 14

Therefore , pH = 14 - 5 = 9

4. 0.01 M KOH

pOH = - log ( 1.0 x 10^ -2)

= 2 - log 1 = 2

pH + pOH = 14

Therefore, pH = 14 - 2 = 12

8 0

3 years ago