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kondaur [170]
3 years ago
6

Does anyone know how to answer this or what the answer is? My sister is having a hard time figuring this out with her tutor?

Chemistry
1 answer:
ira [324]3 years ago
8 0

Its number four.Hope that helps feel free to ask me questions:)

Brainliest??

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What is the density of a cylinder with a mass of 65.34g, a height of 15.60 cm and a radius of 1.34 cm?
jonny [76]

Answer:

d = 0.743 g/cm³

Explanation:

Given data:

Mass of cylinder = 65.34 g

Height = 15.60 cm

Radius = 1.34 cm

Density of cylinder = ?

Solution:

Volume of cylinder:

V = πr²h   (π = 22/7)

V = 88 cm³

Density of cylinder:

d  = m/v

d = 65.34 g / 88 cm³

d = 0.743 g/cm³

5 0
3 years ago
What is the full electric configuration for cadmium?
jekas [21]

Answer: Kr 4d10 5s2

Explanation:

6 0
4 years ago
Please help me! I would appreciate it if you can!
ELEN [110]

Answer:

meteorologist, barometers, anemometer, thermometer, balloon, satellites, station models, isotherms, isobars

Explanation:

4 0
3 years ago
How many molecules would there be in 10.5 L of carbon dioxide at 40.0 C and 252 kPa
kakasveta [241]

Answer:

6.14×10²³ molecules

Explanation:

Data obtained from the question include:

Volume (V) = 10.5L

Temperature (T) = 40°C

Pressure (P) = 252 kPa

Next, we shall determine the number of mole of CO2 present.

This can be obtained by using the ideal gas equation:

PV = nRT

Volume (V) = 10.5L

Temperature (T) = 40°C = 40°C + 273 = 313K

Pressure (P) = 252 kPa

Gas constant (R) = 8.31 KPa.L/Kmol

Number of mole (n) =.?

PV = nRT

252 x 10.5 = n x 8.31 x 313

Divide both side by 8.31 x 313

n = (252 x 10.5) /(8.31 x 313)

n = 1.02 mole

Therefore, 1.02 mol of CO2 is present.

Now, we can obtain the number of molecules of CO2 present as follow:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02×10²³ molecules.

This means that 1 mole of CO2 also contains 6.02×10²³ molecules.

Now, if 1 mole of CO2 contains 6.02×10²³ molecules,

Then 1.02 mole will contain = 1.02 x 6.02×10²³ = 6.14×10²³ molecules.

Therefore, 6.14×10²³ molecules of CO2 is present.

8 0
4 years ago
What is the electron configuration for iodine
iogann1982 [59]

Hello!

To find electron configuration for Idoine we need to understand the following steps:

  1. Finding the Atom's Atomic Number (tells us the specific number of electrons)
  2. Determining the Charge of the Atom
  3. Understanding the orbitals (Set S [Contains 2], P [Contains 3, Holds 6], D [Contains 5, Holds 10], F [Contains 7, Holds 14], and there are some theoritical ones.) [Overall the sets go SPDFGHIK
  4. Understanding notations in configuartion. The notations display the number of electrons in the atom and set.

In this case, for Iodine. If we follow these rules we can see that the electron configuration is [Kr] 4d^10 5s^2 5p^5. We use Krytpon in front because that is the last full and stable noble gas before this particular element. Atoms are just trying to be stable so the goal is to achieve that full shell.

7 0
3 years ago
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