Answer:
-30.0 ºC
Explanation:
The freezing point depression of a solution is given by the relation:
ΔT = - Kf m, where Kf is the molal freezing point constant of water, and m is the molality of the solute.
The molality, in turn, is given by:
m = mol solute / Kg solvent
We are not given in this question the identity of the solute, but the most typical component in antifreeze is ethylene glycol, and that is what we are going to use here.
We now have all the information required to solve this question.
In 100 grams of fluid we have:
Molar mass ethylene glycol = 62.07 g/mol
mol ethyle glycol = 50 g / 62.07 g/mol = 0.81 mol
Kg solvent = 50 g/ 1000 g/ Kg = 0.050 Kg
m = 0.81 mol / 0.050 Kg = 16.1 m
ΔT = - Kf m = -1.86 ºC/m x 16.1 m = -30.0 ºC
