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Marysya12 [62]
1 year ago
13

18. give the product for the following reactions sequence. a) 3-pentanone b) 2-pentanone c) propanone d) 2-butanone e) methyl pr

opanoate 19. give the product for the following reactions sequence. a) ch3ch2cocl b) ch3ch2cho c) ch3co2ch3 d) ch3ch2cooch3 e) ch3ch2ch2cl 20. give the product for the following reactions sequence. a) ch3ch2cocl b) ch3ch2conhch3 c) ch3conhch2ch3 d) ch3ch2cooch3 e) ch3ch2ch2cl
Chemistry
1 answer:
serg [7]1 year ago
5 0

The product for the following reaction are :

  • 2 - butanone
  • CH₃CH₂COCl
  • CH₃CH₂CONHCH₃

T carboxylic acid is an organic compound. the functional group of carboxylic acid is carboxy. general formula is given as : R - COO⁻.

The reactions are given as follows :

1) the reduction of carboxylic acid into ketone with the organometallic compound is given as follows :

CH₃CH₂COOH     +  CH₃Li   ------>   CH₃CH₂COCH₃

                                                                  2 butanone

2) the reaction of carboxylic acid with SOCl₂ is given as follows :

CH₃CH₂COOH    +   SOCl₂   ----->   CH₃CH₂COCl

3) the reaction of carboxylic acid with CH₃NH₂ is given as follows

CH₃CH₂COOH  +   CH₃NH₂   ----->   CH₃CH₂CONHCH₃

Thus,  The product for the following reaction are :

  • 2 - butanone
  • CH₃CH₂COCl
  • CH₃CH₂CONHCH₃

To learn more about carboxylic acid here

brainly.com/question/4721247

#SPJ4

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At 700 K, the reaction 2SO2(g) + O2(g) <====> 2SO3(g) has the equilibrium constant Kc = 4.3 x 106. At a certain instant, f
nadya68 [22]

Answer:

The system is not in equilibrium and will evolve left to right to reach equilibrium.

Explanation:

The reaction quotient Qc is defined for a generic reaction:

aA + bB → cC + dD

Q=\frac{[C]^{c} *[D]^{d} }{[A]^{a}*[B]^{b}  }

where the concentrations are not those of equilibrium, but other given concentrations

Chemical Equilibrium is the state in which the direct and indirect reaction have the same speed and is represented by a constant Kc, which for a generic reaction as shown above, is defined:

Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a}*[B]^{b}  }

where the concentrations are those of equilibrium.

This constant is equal to the multiplication of the concentrations of the products raised to their stoichiometric coefficients divided by the multiplication of the concentrations of the reactants also raised to their stoichiometric coefficients.

Comparing Qc with Kc allows to find out the status and evolution of the system:

  • If the reaction quotient is equal to the equilibrium constant, Qc = Kc, the system has reached chemical equilibrium.
  • If the reaction quotient is greater than the equilibrium constant, Qc> Kc, the system is not in equilibrium. In this case the direct reaction predominates and there will be more product present than what is obtained at equilibrium. Therefore, this product is used to promote the reverse reaction and reach equilibrium. The system will then evolve to the left to increase the reagent concentration.
  • If the reaction quotient is less than the equilibrium constant, Qc <Kc, the system is not in equilibrium. The concentration of the reagents is higher than it would be at equilibrium, so the direct reaction predominates. Thus, the system will evolve to the right to increase the concentration of products.

In this case:

Q=\frac{[So_{3}] ^{2} }{[SO_{2} ]^{2}* [O_{2}] }

Q=\frac{10^{2} }{0.10^{2} *0.10}

Q=100,000

100,000 < 4,300,000 (4.3*10⁶)

Q < Kc

<u><em> The system is not in equilibrium and will evolve left to right to reach equilibrium.</em></u>

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Answer : Option D) The particles move enough that they are not fixed in place, and the liquid can flow.

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