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Marysya12 [62]
1 year ago
13

18. give the product for the following reactions sequence. a) 3-pentanone b) 2-pentanone c) propanone d) 2-butanone e) methyl pr

opanoate 19. give the product for the following reactions sequence. a) ch3ch2cocl b) ch3ch2cho c) ch3co2ch3 d) ch3ch2cooch3 e) ch3ch2ch2cl 20. give the product for the following reactions sequence. a) ch3ch2cocl b) ch3ch2conhch3 c) ch3conhch2ch3 d) ch3ch2cooch3 e) ch3ch2ch2cl
Chemistry
1 answer:
serg [7]1 year ago
5 0

The product for the following reaction are :

  • 2 - butanone
  • CH₃CH₂COCl
  • CH₃CH₂CONHCH₃

T carboxylic acid is an organic compound. the functional group of carboxylic acid is carboxy. general formula is given as : R - COO⁻.

The reactions are given as follows :

1) the reduction of carboxylic acid into ketone with the organometallic compound is given as follows :

CH₃CH₂COOH     +  CH₃Li   ------>   CH₃CH₂COCH₃

                                                                  2 butanone

2) the reaction of carboxylic acid with SOCl₂ is given as follows :

CH₃CH₂COOH    +   SOCl₂   ----->   CH₃CH₂COCl

3) the reaction of carboxylic acid with CH₃NH₂ is given as follows

CH₃CH₂COOH  +   CH₃NH₂   ----->   CH₃CH₂CONHCH₃

Thus,  The product for the following reaction are :

  • 2 - butanone
  • CH₃CH₂COCl
  • CH₃CH₂CONHCH₃

To learn more about carboxylic acid here

brainly.com/question/4721247

#SPJ4

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Answer: Option A

<u>Explanation:</u>

Water is one of the most important constituents of living being. It is said that there is no life without water. So that water need to neutral in nature to save life. Pure water is composed of hydronium H^{+} and hydroxide \left(O H^{-}\right) ions. It is known that hydronium ions are acidic in nature with concentration of 1 \times 10^{-7} \mathrm{M} / \mathrm{L}.

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3 years ago
Read 2 more answers
Determine the equilibrium constant, Kp, for the following reaction, by using the two reference equations below: 2 NO(g) + O2(g)
klio [65]

Answer:

Kp=3.07x10^6

Explanation:

Hello,

In this case, by knowing the given reference reactions, one could rearrange them as follows:

2 NO(g) \leftrightarrow N_2(g) + O_2(g); Kp_2 = \frac{1}{2.3 x 10^{-19}}=4.35x10^{18}

N_2(g) + 2O_2(g) \leftrightarrow 2NO_2(g);Kp_3=(8.4x10^{-7})^2=7.056x10^{-13}

Subsequently, to obtain the main reaction, we add the aforementioned reference rearranged reactions as shown below (just as reference):

2NO(g)+N_2(g)+2O_2\leftrightarrow 2NO_2(g)+N_2+O_2

Consequently, the equilibrium constant is computed as:

Kp=\frac{[N_2][O_2]}{[NO]^2} * \frac{[NO_2]^2}{[N_2][O_2]^2} =Kp_2*Kp_3=4.35x10^{18}*7.056x10^{-13}=3.07x10^6

Best regards.

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sergejj [24]
Google said

How many electrons fit in each shell around an atom?

The maximum number of electrons that can occupy a specific energy level can be found using the following formula:

Electron Capacity = 2n2

The variable n represents the Principal Quantum Number, the number of the energy level in question.

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Keep in mind that an energy level need not be completely filled before electrons begin to fill the next level. You should always use the Periodic Table of Elements to check an element's electron configuration table if you need to know exactly how many electrons are in each level.
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