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S_A_V [24]
4 years ago
15

What is the solution set for this inequality? -8x-40 (greater than) -16

Mathematics
1 answer:
Ulleksa [173]4 years ago
4 0

Answer:

x < -3

Step-by-step explanation:

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Two buses are moving towards each other, one at a speed of 40 mph and the other at a speed of 50 mph. How much closer to each ot
Luba_88 [7]

Answer:

180 miles

Step-by-step explanation:

The are moving towards each other at 50 mph and 40 mph which is the same as 90 mph. They are moving 90 mph closer to each other every hour so in 2 hours it would be 180 miles.

5 0
3 years ago
WILL MARK BRAINIEST, IF U ANSWER **ALL** of these questions! xx
eduard

Answer:

80.029

Step-by-step explanation:

(8)(10)+2+1/100+9(1/1000)

=80+2+1/100+9(1/1000)

=80+201/100+9(1/1000)

=8201/100+9(1/1000)

=8201/100+9/1000

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7 0
3 years ago
In a certain Algebra 2 class of 27 students, 5 of them play basketball and 12 of them play baseball. There are 2 students who pl
drek231 [11]

Answer:

p= \frac{22}{27} =0.814 = 81.4%

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Write a linear equation in the form y=mx+b
Vera_Pavlovna [14]
Y = -2x - 3

When I put this into y2-y1/x2-x1 (equation to find slope) I did the coordinate pairs (3,-9) and (4,-11). When you plug it in it’s -11+9/4-3. This gets you -2/1, which is -2. That’s your slope. Then, in order to get the y-intercept, you can use any of those pairs. I did -9 = 3(-2) + b. -9=-6 + b and in the end this gets you -3 = b. So the full equation is y = -2x - 3.
6 0
2 years ago
A man has 2 pennies, 3 nickels, 1 dime, and 2 quarters. How many different sums of money can he make using one or more of these
Gnesinka [82]
<h2>Explanation</h2><h2></h2><h2>He can use the 2 pennies in 3 ways, take none, take 1 or take 2</h2><h2>He can use the 3 nickels in 4 ways, take none, take 1, etc</h2><h2>the dime in 2 ways,</h2><h2>and the quarters in 3 ways</h2><h2 /><h2>total number of ways = (3)(4)(2)(3) = 72</h2><h2>but that includes taking none of any coins,</h2><h2 /><h2>so number of ways to use the coins is 71</h2><h2 /><h2>Here is a little silly computer program that finds and lists all the possible sumes</h2><h2 /><h2>10 for p = 0 to 2</h2><h2>20 for n = 0 to 3</h2><h2>30 for d = 0 to 1</h2><h2>40 for q = 0 to 2</h2><h2>50 sum = p+5*n+10*d+25*q</h2><h2>60 print sum,</h2><h2>70 next q</h2><h2>80 next d</h2><h2>90 next n</h2><h2>100 next p</h2><h2>>run</h2><h2>0 25 50 10 35 60 5 30 55 15 40 65 10 35 60 20</h2><h2>45 70 15 40 65 25 50 75 1 26 51 11 36 61 6 31</h2><h2>56 16 41 66 11 36 61 21 46 71 16 41 66 26 51 76</h2><h2>2 27 52 12 37 62 7 32 57 17 42 67 12 37 62 22</h2><h2>47 72 17 42 67 27 52 77</h2><h2 /><h2>Notice there are duplications,</h2><h2>e.g. picking 2 nickels or 1 dime yields the same sum</h2><h2 /><h2>All you have to do is eliminate all duplications, and not count the 0</h2><h2>I think there are 47 or them</h2>
4 0
3 years ago
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