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Karolina [17]
3 years ago
14

A man has 2 pennies, 3 nickels, 1 dime, and 2 quarters. How many different sums of money can he make using one or more of these

8 coins? I’ll mark brainliest for the answer that includes an explanation :)
Mathematics
1 answer:
Gnesinka [82]3 years ago
4 0
<h2>Explanation</h2><h2></h2><h2>He can use the 2 pennies in 3 ways, take none, take 1 or take 2</h2><h2>He can use the 3 nickels in 4 ways, take none, take 1, etc</h2><h2>the dime in 2 ways,</h2><h2>and the quarters in 3 ways</h2><h2 /><h2>total number of ways = (3)(4)(2)(3) = 72</h2><h2>but that includes taking none of any coins,</h2><h2 /><h2>so number of ways to use the coins is 71</h2><h2 /><h2>Here is a little silly computer program that finds and lists all the possible sumes</h2><h2 /><h2>10 for p = 0 to 2</h2><h2>20 for n = 0 to 3</h2><h2>30 for d = 0 to 1</h2><h2>40 for q = 0 to 2</h2><h2>50 sum = p+5*n+10*d+25*q</h2><h2>60 print sum,</h2><h2>70 next q</h2><h2>80 next d</h2><h2>90 next n</h2><h2>100 next p</h2><h2>>run</h2><h2>0 25 50 10 35 60 5 30 55 15 40 65 10 35 60 20</h2><h2>45 70 15 40 65 25 50 75 1 26 51 11 36 61 6 31</h2><h2>56 16 41 66 11 36 61 21 46 71 16 41 66 26 51 76</h2><h2>2 27 52 12 37 62 7 32 57 17 42 67 12 37 62 22</h2><h2>47 72 17 42 67 27 52 77</h2><h2 /><h2>Notice there are duplications,</h2><h2>e.g. picking 2 nickels or 1 dime yields the same sum</h2><h2 /><h2>All you have to do is eliminate all duplications, and not count the 0</h2><h2>I think there are 47 or them</h2>
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14tx=46;x=32 what's the answer?​
pickupchik [31]

First plug 32 in for x 14(32)t=46

Now solve for t

448t=46

T=46/448 which can be simplified to 23/224

3 0
3 years ago
Read 2 more answers
Find the 10th partial sum of the arithmetic sequence defined by
Evgesh-ka [11]

Answer:

22.5


Step-by-step explanation:

If you expand the series, you can see the first few terms of the series:

  • Putting 1 in n, \frac{1}{2}(1)-\frac{1}{2}=0
  • Putting 2 in n, \frac{1}{2}(2)-\frac{1}{2}=0.5
  • Putting 3 in n, \frac{1}{2}(3)-\frac{1}{2}=1
  • Putting 4 in n, \frac{1}{2}(4)-\frac{1}{2}=1.5

We can see the series is 0, 0.5, 1, 1.5, ....

This is an arithmetic series with common difference (the difference in 2 terms) 0.5 and first term 0.

We know formula for sum of arithmetic series:

s_{n}=\frac{n}{2}(2a+(n-1)d)

Where,

  • S_{n} denotes the nth partial sum
  • a is the first term (in our case it is 0)
  • n is the term (in our case it is 10 since we want to find 10th partial sum -- sum until first 10 terms)
  • d is the common difference (difference in term and the previous term) (in our case it is 0.5)

Substituting these into the formula, we get the 10th partial sum to be:

s_{10}=\frac{10}{2}(2(0)+(10-1)(0.5))\\s_{10}=5(0+(9)(0.5))\\s_{10}=5(0+4.5)\\s_{10}=5(4.5)\\s_{10}=22.5

So the sum of the first 10 terms is 22.5. Third answer choice is right.


8 0
3 years ago
Read 2 more answers
Please help me need ASAPp
ipn [44]
It is the 4th option 0
7 0
3 years ago
Can you please help me
andrezito [222]

Answer:

its kinda dificult to explain (easier to show) but ill do my best

Step-by-step explanation:

so for part a you wanna start from the bottom (min) and go acros to the line above 1 then  go three lines up for cookies. you should be on 3, 1

for part b its c lin decorates 21 cookies in 7 min

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3 years ago
Find the slope and y intercept<br><img src="https://tex.z-dn.net/?f=%20-%206x%20%2B%204y%20%3D%20%20-%2012" id="TexFormula1" tit
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The correct answer would be : Slope : 3/2 and Y-Intercept : −3

I hope that this helps you !

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3 years ago
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