What is the result of subtracting the second equation from the first?
1 answer:
Answer:
Step-by-step explanation:
For this exercise you need to remember:
1) The mulitplication of signs:
2) By definition, like terms contain the same variables with the same exponent.
Then knowing this, and given the equations:
and
You must subtract the like terms, which means that you must subtract the numerical coefficients of each term.
Then, you get the result is:
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Answer:
C: <u>19</u>
Step-by-step explanation:
To start we would resolve the absolute value of . We know that absolute value is the distance from zero so it would be 3.
Our new equation is
Now we need to solve in the order of PEDMAS starting with parenthesis to get
Next in PEDMAS we have Division/Multiplication since we don't have any exponents. We do all the division and multiplication left to right so we would divide to get and then multiply to get
.
Finally, we only have addition left over so our answer would be
A linear function has the form : f(x)=ax+b
we are given that
f(0)=a*0+b=b is <span>$14,500.
so the sales in the first year were </span>$14,500.
f(1) gives the sales in the second year (year 83)
f(2) gives the sales in the third year (year 84)
.
.
f(5) gives the sales in the sixths year (year 87)
the slope of the line, a, is given by :
thus,
S=ax+b=10,200x+<span>14,500
</span>
Answer: S=10,200x+14,500
we are given that
f(0)=a*0+b=b is <span>$14,500.
so the sales in the first year were </span>$14,500.
f(1) gives the sales in the second year (year 83)
f(2) gives the sales in the third year (year 84)
.
.
f(5) gives the sales in the sixths year (year 87)
the slope of the line, a, is given by :
thus,
S=ax+b=10,200x+<span>14,500
</span>
Answer: S=10,200x+14,500