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zysi [14]
3 years ago
11

What is the pattern of the table! (wait adding picture)

Mathematics
1 answer:
iogann1982 [59]3 years ago
8 0
I don't know how to word it right now but it's adding up by odds: +1, +3, +5, +7...
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What is the product of 136.4 and 0.47?
solniwko [45]

Answer:

64.108

136.3x0.47=64.108

i did it ona calculator

5 0
3 years ago
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Yancey collects plastic banks .He has three different banks: a pig, a cow, and a horse. How many ways can Yancey arrange his ban
Stells [14]


let h = horse, let c = cow, let p = pig

so,

hcp

hpc

cph

chp

phc

pch

so, that is 6 different ways she can arrange it.  

4 0
3 years ago
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An electrician sent Bonnie an invoice in the amount of 'a' dollars for 6 hours of work that was done on Saturday. The electricia
Mazyrski [523]

Answer:

(a-f)/6 = r

Step-by-step explanation:

The total Bonnie must pay is the weekend fee plus the hourly rate times the hours worked

Cost = weekend fee * hourly rate* hours

hours = 6

weekend fee =f

hourly rate = r

Cost = a dollars

Substituting in what we know

a = f+ 6r

We want to solve for r

Subtract f from each side

a-f =f-f +6r

a-f = 6r

Divide each side by 6

(a-f)/6 = 6r/6

(a-f)/6 = r

4 0
3 years ago
I need to know the equations
dem82 [27]
Let l, t, b represent the numbers of lions, tigers, bears, respectively.

2l +3t +3b = 156 . . . . . . . 156 meals per day are supplied
l +t = 3b . . . . . . . . . . . . . . there are 3 times as many great cats as bears
l +t +b = 68 . . . . . . . . . . . there are a total of 68 animals

_____
The last 2 equations tell you
.. 4b = 68
.. b = 17
Subtracting 3 times the last equation from the first gives
.. -l = -48
There are 48 lions, 3 tigers, and 17 bears.
4 0
3 years ago
Read 2 more answers
B: Alex is 12 years older than George.
UkoKoshka [18]

Answer:

The ratio of George age to Carl's age is 1:12.

Step-by-step explanation:

Let the age of George be 'g'.

Let the age of Alex be 'a'.

Also Let the age of Carl be 'c'.

Given:

The sum of their ages is 68.

So equation can be framed as;

g+a+c=68 \ \ \ \ equation 1

Also Given:

Alex is 12 years older than George.

So equation can be framed as;

a =g+12 \ \ \ \ equation \ 2

Now Given:

Carl is three times older than Alex.

c=3a

But a =g+12

So we get;

c = 3(g+12) \\\\c= 3g+36 \ \ \ \ equation \ 3

Now Substituting equation 2 and equation 3 in equation 1 we get;

g+a+c=68\\\\g+g+12+3g+36=68\\\\5g+48=68

Subtracting both side by 48 using subtraction property of equality we get;

5g+48-48=68-48\\\\5g=20

Now Dividing both side by 5 using Division property of equality we get;

\frac{5g}{5}=\frac{20}{5}\\\\g =4

Hence George age g = 4 \ years

Now Alex age a=g+12 = 4+12 =16\ years

Also Carl's age c=3g+36=3\times 4+36 =12+36 =48\ years

Now we need to find the ratio of George age to Carl's age.

\frac{g}{c}=\frac{4}{48} = \frac{1}{12}

Hence  the ratio of George age to Carl's age is 1:12.

3 0
3 years ago
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