let h = horse, let c = cow, let p = pig
so,
hcp
hpc
cph
chp
phc
pch
so, that is 6 different ways she can arrange it.
Answer:
(a-f)/6 = r
Step-by-step explanation:
The total Bonnie must pay is the weekend fee plus the hourly rate times the hours worked
Cost = weekend fee * hourly rate* hours
hours = 6
weekend fee =f
hourly rate = r
Cost = a dollars
Substituting in what we know
a = f+ 6r
We want to solve for r
Subtract f from each side
a-f =f-f +6r
a-f = 6r
Divide each side by 6
(a-f)/6 = 6r/6
(a-f)/6 = r
Let l, t, b represent the numbers of lions, tigers, bears, respectively.
2l +3t +3b = 156 . . . . . . . 156 meals per day are supplied
l +t = 3b . . . . . . . . . . . . . . there are 3 times as many great cats as bears
l +t +b = 68 . . . . . . . . . . . there are a total of 68 animals
_____
The last 2 equations tell you
.. 4b = 68
.. b = 17
Subtracting 3 times the last equation from the first gives
.. -l = -48
There are 48 lions, 3 tigers, and 17 bears.
Answer:
The ratio of George age to Carl's age is 1:12.
Step-by-step explanation:
Let the age of George be 'g'.
Let the age of Alex be 'a'.
Also Let the age of Carl be 'c'.
Given:
The sum of their ages is 68.
So equation can be framed as;

Also Given:
Alex is 12 years older than George.
So equation can be framed as;

Now Given:
Carl is three times older than Alex.

But 
So we get;

Now Substituting equation 2 and equation 3 in equation 1 we get;

Subtracting both side by 48 using subtraction property of equality we get;

Now Dividing both side by 5 using Division property of equality we get;

Hence George age 
Now Alex age 
Also Carl's age 
Now we need to find the ratio of George age to Carl's age.

Hence the ratio of George age to Carl's age is 1:12.