For the answer to the question above asking<span> what is the measure of an acute base angle of the trapezoid?
</span>n acute base angle of the trapezoid would be the same as the triangle.
<span>subtract 34º from 180º, then divide by 2. </span>
<span>(180 - 34)/2 = 73º
</span>I hope my answer helped you.
<h2>3.14 units²</h2><h3><em>(Assuming pi equals 3.14)</em></h3><h3><em></em></h3><h3>A = pi(radius²)</h3><h3></h3><h3>1² = 1</h3><h3>1 x 3.14 = 3.14</h3>
What is the separate weight
Answer:
CA=17
Step-by-step explanation:
From given picture we see that A and C are the mid points of sides QR and QS respectively.
We know that line joining mid points of the two sides of triangle is always half of the length of the third side.
So that means:
2*CA=SR
2(3x-1)=5x+4
6x-2=5x+4
6x-5x=4+2
x=6
plug value of x into CA=3x-1
CA=3*6-1=18-1=17
Hence final answer is CA=17
Since they are vertical they are equal to each other.
3x + 4 = 7x - 9
4 = 4x - 9
13 = 4x
3.25 = x
So the value of x is 3.25.
Hope this helps :)
