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MA_775_DIABLO [31]
4 years ago
5

A resistor and a capacitor are connected in series across an ideal battery having a constant voltage across its terminals. (a) A

t the moment contact is made with the battery the voltage across the capacitor is A resistor and a capacitor are connected in series across an ideal battery having a constant voltage across its terminals. (b) At the moment contact is made with the battery the voltage across the capacitor is greater that the battery's terminal voltage. equal to the battery's terminal voltage. less than the battery's terminal voltage, but greater than zero. zero.
Physics
1 answer:
mariarad [96]4 years ago
8 0

Answer:

The question is not complete. see the complete question in the explanation section. The correct option is highlighted in bold

Explanation:

(a)A resistor and a capacitor are connected in series across an ideal battery having a constant voltage across its terminals. At the moment contact is made with the battery, the voltage across the resistor is

I.     greater than the battery's terminal voltage.  

II.    equal to the battery's terminal voltage.  

III.  less than the battery's terminal voltage, but greater than zero.  

IV.  zero.

<em>Option (i) is not correct as the voltage across the resistor cannot be greater than the terminal voltage since the current is yet to flow through the resistor. Option (ii) is correct as both the resistor voltage and the terminal voltage will just equal at the instance of connection. Option (ii) can only be possible after the current must have passed through the resistor for a while not immediately after contact. Option (iv) is not correct, as this can only be possible is the contact is open. </em>

(b)A resistor and a capacitor are connected in series across an ideal battery having a constant voltage across its terminals. At the moment contact is made with the battery the voltage across the capacitor is  

I.   greater than the battery's terminal voltage.  

II.  equal to the battery's terminal voltage.  

III. less than the battery's terminal voltage, but greater than zero.  

IV. zero.

<em>Option (i) is not correct as the capacitor is yet to charge talk less of the its voltage exceeding that of the battery. Option (ii) can only be correct if the capacitor is fully charged not when it has just been connected. Option (iii) can only occur if the capacitor is discharging. Option (iv) is the correct answer as the capacitor is about to start charging </em>

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Respiratory system.

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4 years ago
You stand on a bridge above a river and drop a rock into the water below from a height of 25 m. (Assume no air resistance)
Ilia_Sergeevich [38]

PART a)

here when stone is dropped there is only gravitational force on it

so its acceleration is only due to gravity

so we will have

a = g = 9.8 m/s^2

Part b)

Now from kinematics equation we will have

y = v_i t + \frac{1}{2} at^2

now we have

y = 25 m

so from above equation

25 = 0 + \frac{1}{2}(9.8 )t^2

t = 2.26 s

Part c)

If we throw the rock horizontally by speed 20 m/s

then in this case there is no change in the vertical velocity

so it will take same time to reach the water surface as it took initially

So t = 2.26 s

Part D)

Initial speed = 20 m/s

angle of projection = 65 degree

now we have

v_x = vcos\theta

v_x  = 20 cos65 = 8.45 m/s

v_y = vsin\theta

v_y = 20 sin65 = 18.13 m/s

PART E)

when stone will reach to maximum height then we know that its final speed in y direction becomes zero

so here we can use kinematics in Y direction

v_f - v_y = at

0 - 18.13 = (-9.8) t

t = 1.85 s

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5 0
3 years ago
Sound is a longitudinal wave that travels at speed 343343m/s in dry air at room temperature and standard pressure. Your ear is c
finlep [7]

Answer:

d = 0.343 m

Explanation:

Given that,

The speed of a longitudinal wave, v = 343 m/s

Your ear is capable of differentiating sounds that arrive at the ear just 1.00 milliseconds apart.

We need to find the minimum distance between two speakers that produce sounds that arrive at noticeably different times.

Let the distance be d. So,

d=v\times t\\\\=343\times 10^{-3}\\\\=0.343\ m

So, the required distance is equal to 0.343 m.

6 0
3 years ago
A lacrosse ball leaves the sick horizontally at 12.0m/s. the catcher is 14.0 away. How much does the ball fall vertically travel
boyakko [2]

Answer:

1.65 m

Explanation:

The motion of the ball is a projectile motion, so it is a parabolic motion with two independent motions:

- on the x-axis, a uniform motion with constant speed v_x=12.0 m/s

- on the y-axis, a uniformly accelerated motion with constant acceleration a=9.8 m/s^2 downward.

First of all, we need to find the time t at which the ball has travelled halfway to the chatcher, i.e. at a distance of x=14.0/2=7.0 m. This can be found by using the relationship between distance, time and velocity along the horizontal direction:

t=\frac{x}{v_x}=\frac{7.0 m}{12.0 m/s}=0.58 s

So now we can move to the vertical motion, and we can calculate the distance covered vertically by the ball while falling for t=0.58 s, by using:

S=\frac{1}{2}at^2=\frac{1}{2}(9.8 m/s^2)(0.58 s)^2=1.65 m

7 0
3 years ago
On the same spring day, a station near the equator has a surface temperature of 25°C, 15°C higher than the middle-latitude city
DedPeter [7]

Answer:

The air temperature at the tropopause is - 79 °C

Explanation:

We know that a station near the equator has a surface temperature of 25°C

Vertical soundings reveal an environmental lapse rate of 6.5 °C per kilometer.

The tropopause is encountered at 16 km.

In order to find the air temperature at the tropopause we are going to deduce a linear function for the temperature at the tropopause.

This linear function will have the following structure :

f(x)=ax+b

Where ''a'' and ''b'' are real numbers.

Let's write T(x) to denote the temperature '' T '' in function of the distance

'' x '' ⇒

T(x)=ax+b

We can reorder the function as :

T(x)=b+ax (I)

Now, at the surface the value of ''x'' is 0 km and the temperature is 25°C so in the function (I) we write :

T(0)=25=b+a(0) ⇒ b=25 ⇒

T(x)=25+ax (II)

In (II) the value of ''a'' represents the change in temperature per kilometer.

Because the temperature decrease with the height this number will be negative and also a data from the question ⇒

T(x)=25-(6.5)x (III)

In (III) we deduced the linear equation. The last step is to replace by x=16 in (III) ⇒

T(16)=25-(6.5)(16)=-79

The air temperature at the tropopause is - 79 °C

6 0
3 years ago
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