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sergiy2304 [10]
4 years ago
11

at 20 c a length of copper wire has a resistance of 5.0. What is its resistance when the wire is heated to 80c? let a=.0004 at 2

0c.
Physics
1 answer:
AysviL [449]4 years ago
6 0

Answer:

R=5.12\ \Omega

Explanation:

<u>Electric Resistance and Temperature </u>

For some materials, resistivity is linearly related to the temperature. The function that relates them is

R=R_o[1+\alpha (T-T_o)]

Where Ro is the electric resistance at 20°C, \alpha is the temperature coefficient of the conductor, T is the actual temperature at which we want to compute R, and To is the initial temperature, usually 20°C.

The problem gives us the following values

R_o=5\ \Omega,\ T_o=20^oC,\ \alpha=0.0004\ ^oC^{-1},\ T=80^oC

Thus

R=5[1+0.0004 (80-20)]=5.12\ \Omega

\boxed{R=5.12\ \Omega}

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23.
Volgvan

Answer:

1 m = 100 cm....so 2.5 m = (2.5 * 100) = 250 cm

a = 1st shelf

b = 2nd

c = 3rd

d = 4th

a + b + c + d = 250

b = 2a + 18

c = a - 12

d = a + 4

a + (2a + 18) + (a - 12) + (a + 4) = 250

5a + 10 = 250

5a = 250 - 10

5a = 240

a = 240/5

a = 48 cm <== 1st shelf

b = 2a + 18 = 2(48) + 18 = 114 cm <== 2nd shelf

c = a - 12 = 48 - 12 = 36 cm <== 3rd shelf

d = a + 4 = 48 + 4 = 52 cm <== 4th shelf

so 2nd shelf is 114 cm

4 0
3 years ago
A driver drives a car up a hill. The driver keeps pressing the gas so that the engine increases the force it applies to the car.
iris [78.8K]

Answer:

because it's on an upward climb therefore newton's law of motion is in place and you're car is pulled by gravity

6 0
3 years ago
Whu is it important to mave regular supervision of weights and measurements in the market​
pentagon [3]

Answer:

Hope the answer helped you. if yes pls follow me

Explanation:

the fundamental answer is without regular supervision of definition of weights and measures,commerce exchange will be impossible and there would be no market whatsoever for anything.

5 0
3 years ago
n general, which trophic level has the LEAST energy available to it? A) producer B) primary consumer C) secondary consumer D) te
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D - tertiary consumer

This is because it is the farther up to food chain.  
4 0
3 years ago
A comet is in an elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4.6 multiply 1010 m (inside t
Doss [256]

We will apply the concepts related to energy conservation to develop this problem. In this way we will consider the distances and the given speed to calculate the final speed on the path from the sun. Assuming that the values exposed when saying 'multiply' is scientific notation we have the following,

d_1 = 4.6*10^{10}m

v_i = 9.3*10^4m/s \rightarrow \text{Initial velocity comet}

d_2 = 6*10^{12}m

The difference of the initial and final energy will be equivalent to the work done in the system, therefore

E_f = E_i +W

K_f +U_f = K_i +U_i + 0

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Here,

m = Mass

v_f = Final velocity

G = Gravitational Universal Constant

M = Mass of the Sun

m = Mass of the comet

v_i = Initial Velocity

Rearranging to find the final velocity,

v_f = \sqrt{v_i^2+2GM(\frac{1}{d_2}-\frac{1}{d_1})}

Replacing with our values we have finally,

v_f = \sqrt{(9.3*10^4)+2(6.7*10^{-11})(1.98*10^{30})(\frac{1}{6*10^{12}}-\frac{1}{4.6*10^{10}})}

v_f = 75653.9m/s

Therefore the speed is 75653m/s

8 0
4 years ago
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