Answer:
Correct answer: F₂ = 104.5 N
Explanation:
Given:
m = 57 g = 57 · 10⁻³ kg
Δt = 30 ms = 30 · 10 ⁻³ seconds
V₁ = 73.14 m/s service speed
V₂ = 55 m/s returned speed
M = m · V Momentum or Impulse
You forgot to indicate what time the ball contact when returning.
We will assume that the time is the same Δt = 30 ms = 30 10 ⁻³ seconds.
The formula for calculating force is according to Newton's second law is:
F = ΔM / Δt = m · ΔV / Δt
Force during service is:
F₁ = 57 · 10⁻³ · 73.14 / 30 · 10 ⁻³ = 138.97 N
F₁ = 138.97 N
Returned force:
F₂ = 57 · 10⁻³ · 55 / 30 · 10 ⁻³ = 104.5 N
F₂ = 104.5 N
God is with you!!!
Answer:
<em>Hello, The velocity of the ball is 0.92 m/s in the downward direction (-0.92 m/s).</em>
Explanation:
The equation for the velocity of an object thrown upward is the following:
v = v0 + g · t
Where:
v = velocity of the ball.
v0 = initial velocity.
g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive).
t = time.
To find the velocity of the ball at t = 0.40 s, we have to replace "t" by 0.40 s in the equation:
v = v0 + g · t
v = 3.0 m/s - 9.8 m/s² · 0.40 s
v = -0.92 m/s
The velocity of the ball is 0.92 m/s in the downward direction (-0.92 m/s).
<em>Hope That Helps!</em>
Answer:
The tangential speed of the ball is 11.213 m/s
Explanation:
The radius is equal:
(ball rotates in a circle)
If the system is in equilibrium, the tension is:
Replacing:
Replacing:
Answer:
They will not meet
h-hX=1.2*g*t²
hX=v0*t-(1/2*g*t²)
Explanation:
fall h=1/2*g*t²
elevation time if v0=20 m/s te=v0/g=20 m/s /9.81 m/s²=2.0387s
hmax=v0²/(2*g)=(400 m²/s²)/19.62 m/s²2=20.387 m
free fall
t=2.0387s yields hX=1/2*g*t²=20.387 m
h-hX=200m - 20.387 m=179,613 m.
so, the second body has not enough initianoal speed to reach a meeting point
