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melamori03 [73]
3 years ago
15

When an atom releases gamma radiation____________.

Physics
1 answer:
wel3 years ago
3 0

Answer:

d. the atomic number remains the same.

Explanation:

First at all it's important to know how to read nuclear information

_{Z}^{A}X

X is the atomic symbol, A the mass number and Z the atomic number of the element.

Gamma rays emitted on gamma decay are characterized as _{0}^{0}\gamma

If we write the nuclear equation for the decay, we have that:

_{Z}^{A}X\,\rightarrow{}_{0}^{0}\gamma\,+\,{}_{Z}^{A}Y

The sum of the mass numbers and atomic numbers on the right side has to be equal to the left side numbers of the equation, that means the mass number and the atomic number remains the same for the resulting atom to preserve the equality.

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A 7800 W lift took 10 seconds to move a 5000 N weight. How far did the lift move this weight?
Eduardwww [97]

Answer:

Both are moving at 30 km/h, so their speed is the same. ... enough fuel for the trip/how long it will take. 4 Weight is a force, and so is a vector. ... c At 10 seconds David's displacement is.

7 0
3 years ago
When Javier touches a hot mug of tea, energy is transferred from the surface of the mug to his hand. What kind of energy is this
sweet [91]

Answer:

Thermal energy

Explanation:

  • When work is being done energy is being transferred.
  • <em><u>Work can transfer energy between objects and cause a change in the form of energy.</u></em>
  • Thermal energy is a type of energy that is generated from heat. It is an example of kinetic energy that involves motion of particles.
  • <em><u>When  Javier touches a hot mug of tea, </u></em><em><u>thermal energy </u></em><em><u>is transferred from the surface of the mug to his hand through conduction.</u></em>

5 0
3 years ago
Read 2 more answers
Question 2 of 10 Which process is the source of all the thermal energy produced by a nuclear reactor? O A. Radioactive decay B.
sukhopar [10]

Answer:

C

Explanation:

A P E X

6 0
3 years ago
A 0.250-kg aluminum bowl holding 0.800 kg of soup at 27.6°C is placed in a freezer. What is the final temperature if 424 kJ of e
erastovalidia [21]

Answer:

16.32 °C

Explanation:

We are given;

Mass of aluminum bowl; m_b = 0.25 kg

Mass of soup; m_s = 0.8 kg

Thus, formula to find the amount of heat energy for a temperature change of 27.6°C to 0°C is;

Q = (m_b•c_b•Δt) + (m_s•c_s•Δt)

Where;

c_b = 0.215 kcal/(kg•°C)

c_s = 1 kcal/(kg•°C)

ΔT = 27.6 - 0 = 27.6°C

Thus;

Q = (0.25 × 0.215 × 27.6) + (0.8 × 1 × 27.6)

Q = 23.5635 Kcal

Now, the energy that exits to be used to freeze the soup is;

Q' = 424 kJ - Q

Let's convert 424 KJ to Kcal

424 KJ = 424/4.184 Kcal = 101.3384 Kcal

Thus;

Q' = 101.3384 - 23.5635

Q' = 77.7749 Kcal

Amount of heat that's removed is given by;

Q_f = Q' - mL

Where;

m = m_s = 0.8 kg

L = 79.8 kcal/kg

Thus;

Q_f = 77.7749 - (0.8 × 79.8)

Q_f = 13.9349 Kcal

Then final temperature will be;

T_f = Q_f/((m_b•c_b) + (m_s•c_s))

T_f = 13.9349/((0.25 × 0.215) + (0.8 × 1))

T_f = 16.32 °C

4 0
3 years ago
A lead mass is heated and placed in a foam cup calorimeter containing 50.0 ml of water at 18.0°c. the water reaches a temperatur
maria [59]
Assuming that there is no heat loss, and the cup is perfectly insulated, all of the energy lost by the lead will be absorbed by the water.
The heat absorbed is given by:
Energy = mass * specific heat capacity * change in temperature
The specific heat capacity of water is 4.18 joules per gram.

In order to compute the mass, we will use the fact that the density of water is one gram per milliliter. Therefore, the mass of water is 50 grams.

Now,
Q = 50 * 4.18 * (20 - 18)
Q = 418 J

418 Joules of energy were released by the lead.
4 0
3 years ago
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