Here is the energy that is left after the quantity of energy is transformed: 750 j of electrical energy is changed into 400 j of kinetic or mechanical energy, which is then turned into 0.32 j of efficient energy.
To run the fan, electrical energy is utilized.
Here, under the specified circumstances, 750 J of electrical energy is utilized to operate the fan, which is transformed into 400 J of kinetic energy. As a result, 350 J of energy is wasted due to various frictional and resistive losses.
Therefore, we may conclude that only 400 J of the 750 J available energy is used to power the fan, with the remaining energy being wasted as a result of friction.
Additionally, we can state that this fan's effectiveness will be
n = Useful ÷ Total
n = 400 ÷ 750
n = 8 ÷ 25
n = 0.32
Learn more about energy at
brainly.com/question/15915007?referrer=searchResults
#SPJ4
Answer:
x₁ = 0.1878 m
Explanation:
For this exercise we will use conservation of energy
starting point. Highest point
Em₀ = U = m g h
final point. Lowest point with fully compressed spring
Em_f = K_e + U
Em_f = ½ K x² + m g x
energy is conserved
Em₀ = Em_f
m g h = ½ K x² + m g x
½ K x² + mg (x- h) = 0
let's substitute
½ 7.3 x² + 0.030 9.8 (x- 0.25) = 0
3.65 x² + 0.294 (x- 0.25) = 0
x² + 0.080548 (x- 0.25) = 0
x² - 0.020137 + 0.080548 x = 0
x² + 0.080548 x - 0.020137 = 0
let's solve the quadratic equation
x = [0.080548 ±√ (0.080548² + 4 0.020137)] / 2
x = [0.080548 ± 0.29502] / 2
x₁ = 0.1878 m
x₂ = -0.1072 m
These are the compression and extension displacement of the spring
Answer and Explanation:
Cup 1. The ice cubes are in a solid state.
Cup 2: The cup has water that is liquified.
Cup 3: The cup is empty and only contains free floating air particles.
***If you found my answer helpful, please give me the brainliest. :) ***
Answers:
a) ![\hat F=(0.83,-0.55) N](https://tex.z-dn.net/?f=%5Chat%20F%3D%280.83%2C-0.55%29%20N)
b) ![\hat D=(-0.44,-0.89) m](https://tex.z-dn.net/?f=%5Chat%20D%3D%28-0.44%2C-0.89%29%20m)
c) ![\hat V=(-0.47,0.88) m/s](https://tex.z-dn.net/?f=%5Chat%20V%3D%28-0.47%2C0.88%29%20m%2Fs)
Explanation:
A unit vector is a vector whose magnitude (length) is equal to 1. This kind of vector is identified as
and the way to calculate is as follows:
![\hat v=\frac{\vec v}{|v|}](https://tex.z-dn.net/?f=%5Chat%20v%3D%5Cfrac%7B%5Cvec%20v%7D%7B%7Cv%7C%7D)
Where:
is the vector
is the magnitude of the vector
Having this information clarified, let's begin with the answers:
a) Force Vector
![\vec F=(9.0 \hat i - 6.0 \hat j) N](https://tex.z-dn.net/?f=%5Cvec%20F%3D%289.0%20%5Chat%20i%20-%206.0%20%5Chat%20j%29%20N)
Magnitude of
:
![|F|=\sqrt{(9.0 \hat i)^{2}+(-6.0 \hat j)^{2 }}N=10.81 N](https://tex.z-dn.net/?f=%7CF%7C%3D%5Csqrt%7B%289.0%20%5Chat%20i%29%5E%7B2%7D%2B%28-6.0%20%5Chat%20j%29%5E%7B2%20%7D%7DN%3D10.81%20N)
<u />
<u>Unit vector:</u>
![\hat F=\frac{\vec F}{|F|}](https://tex.z-dn.net/?f=%5Chat%20F%3D%5Cfrac%7B%5Cvec%20F%7D%7B%7CF%7C%7D)
![\hat F=\frac{9.0}{10.81} N-\frac{6.0}{10.81}N](https://tex.z-dn.net/?f=%5Chat%20F%3D%5Cfrac%7B9.0%7D%7B10.81%7D%20N-%5Cfrac%7B6.0%7D%7B10.81%7DN)
![\hat F=(0.83,-0.55) N](https://tex.z-dn.net/?f=%5Chat%20F%3D%280.83%2C-0.55%29%20N)
b) Displacement Vector
![\vec D=(-4.0 \hat i - 8.0 \hat j) m](https://tex.z-dn.net/?f=%5Cvec%20D%3D%28-4.0%20%5Chat%20i%20-%208.0%20%5Chat%20j%29%20m)
Magnitude of
:
![|D|=\sqrt{(-4.0 \hat i)^{2}+(-8.0 \hat j)^{2 }}m=8.94 m](https://tex.z-dn.net/?f=%7CD%7C%3D%5Csqrt%7B%28-4.0%20%5Chat%20i%29%5E%7B2%7D%2B%28-8.0%20%5Chat%20j%29%5E%7B2%20%7D%7Dm%3D8.94%20m)
<u />
<u>Unit vector:</u>
![\hat D=\frac{\vec D}{|D|}](https://tex.z-dn.net/?f=%5Chat%20D%3D%5Cfrac%7B%5Cvec%20D%7D%7B%7CD%7C%7D)
![\hat D=\frac{-4.0}{8.94} Nm+\frac{-8.0}{8.94}m](https://tex.z-dn.net/?f=%5Chat%20D%3D%5Cfrac%7B-4.0%7D%7B8.94%7D%20Nm%2B%5Cfrac%7B-8.0%7D%7B8.94%7Dm)
![\hat D=(-0.44,-0.89) m](https://tex.z-dn.net/?f=%5Chat%20D%3D%28-0.44%2C-0.89%29%20m)
c) Velocity Vector
![\vec V=(-3.50 \hat i + 6.50 \hat j) m/s](https://tex.z-dn.net/?f=%5Cvec%20V%3D%28-3.50%20%5Chat%20i%20%2B%206.50%20%5Chat%20j%29%20m%2Fs)
Magnitude of
:
![|V|=\sqrt{(-3.50 \hat i)^{2}+(6.50 \hat j)^{2}}m/s=7.38 m/s](https://tex.z-dn.net/?f=%7CV%7C%3D%5Csqrt%7B%28-3.50%20%5Chat%20i%29%5E%7B2%7D%2B%286.50%20%5Chat%20j%29%5E%7B2%7D%7Dm%2Fs%3D7.38%20m%2Fs)
<u />
<u>Unit vector:</u>
![\hat V=\frac{\vec V}{|V|}](https://tex.z-dn.net/?f=%5Chat%20V%3D%5Cfrac%7B%5Cvec%20V%7D%7B%7CV%7C%7D)
![\hat V=\frac{-3.50}{7.38} m/s+\frac{6.50}{7.38}m/s](https://tex.z-dn.net/?f=%5Chat%20V%3D%5Cfrac%7B-3.50%7D%7B7.38%7D%20m%2Fs%2B%5Cfrac%7B6.50%7D%7B7.38%7Dm%2Fs)
![\hat V=(-0.47,0.88) m/s](https://tex.z-dn.net/?f=%5Chat%20V%3D%28-0.47%2C0.88%29%20m%2Fs)
Answer:
its 45 over 6
Explanation:the answer is in the question