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spin [16.1K]
3 years ago
10

The Force of friction between an object and the surface upon which it is sliding is 12N. The weight of the object is 20N. What i

s the coefficient of kinetic friction?
Use equation Ffr=Uk(mg)
Physics
2 answers:
shtirl [24]3 years ago
7 0

Answer: The coefficient of kinetic friction is μ = 0.6

Explanation:

For an object of mass M, the weight is:

W = M*g

where g is the gravitational acceleration: g = 9.8m/s^2

And the friction force between this object and the surface can be written as:

F = W*μ

where μ is the coefficient of friction (kinetic if the object is moving, and static if the object is not moving, usually the static coefficient is larger)

In this case, the weight is:

W = 20N

And the friction force is:

F = 12N

Replacing these values in the equation for the friction force we get:

12N = 20N*μ

(12N/20N) = μ = 0.6

The coefficient of kinetic friction is μ = 0.6

Gekata [30.6K]3 years ago
5 0
Hope you have a good year!
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How much work done if an object is moving to the right and a force of 75. 0n is applied at 125 degrees to the motion while the o
bogdanovich [222]

Answer:

-322.64 J

Explanation:

75 N  * cos 125     *    7.5   =  -322.64 J

4 0
2 years ago
Homework help plz it would help a lot ​
blagie [28]

#82

here we know that

acceleration = 2 m/s/s

time = 5 s

initial speed = 4 m/s

now we can use kinematics to find the final speed

v_f = v_i + at

v_f = 4 + 2(5)

v_f = 14 m/s

So correct answer will be option D)

#83

here we know that

acceleration = 3 m/s/s

time = 4 s

initial speed = 5 m/s

now we can use kinematics to find the final speed

v_f = v_i + at

v_f = 5 + 3(4)

v_f = 17 m/s

So correct answer will be option C)

#84

here we know that

acceleration = 7 m/s/s

time = 3 s

initial speed = 8 m/s

now we can use kinematics to find the final speed

v_f = v_i + at

v_f = 8 + 7(3)

v_f = 29 m/s

So correct answer will be option C)

6 0
3 years ago
A parcel of land is in the shape of an isosceles triangle. The base has a length of 425 ft.; the other sides, which are of equal
kogti [31]

Answer:

The answer to your question is 636.6 ft    

Explanation:

Data

base = 425 ft

angle = 39°

See the picture below

1.- Divide the triangle to get two right triangles.

    Now the superior angle will measure 19.5° and the opposite side will measure 212.5 ft

2.- Use the trigonometric function sine to find the hypotenuse

     sin 19.5 = 212.5/hyp

solve for hyp

    hyp = 212.5 / sin 19.5

Result

    hyp = 212.5/ 0.333

    hyp = 636.6 ft    

4 0
2 years ago
# A cheetah can start from rest and attain the velocity 72km/h in 2 seconds. Calculate the acceleration of cheetah
yan [13]

Answer:

<h2>10 \: m/s ^2</h2><h2 />

Explanation:

Solution,

When a certain object comes in motion from rest, in the case, initial velocity = 0 m/s

Initial velocity ( u ) = 0 m/s

Final velocity ( v ) = 72 km/h ( Given)

We have to convert 72 km /h in m/s

72 \: km \: per \: hour

= 72 \times  \frac{1000}{60  \times 60}

= 20 m/s

Final velocity ( v ) = 20 m/s

Time taken ( t ) = 2 seconds

Acceleration (a) = ?

Now,

we have,

a =  \frac{v - u}{t}

a =  \frac{20 - 0}{2}

a =  \frac{20}{2}

a = 10 m/s ^2

Hope this helps...

Good luck on your assignment..

7 0
3 years ago
1. Indica cuáles son los reactivos y productos de la reacción química representada por la ecuación siguiente, y señala en que es
bearhunter [10]

Answer:

Los reactivos, con su correspondiente estado de agregación, son:

  • Mg: estado sólido
  • HCl: estado acuoso

Los productos, con su correspondiente estado de agregación, son:

  • MgCl₂: estado acuoso
  • H₂: estado gaseoso

Explanation:

Una reacción química es un proceso por el cual una o más sustancias se transforman en otra u otras sustancias con propiedades diferentes. En otras palabras, las reacciones químicas son procesos en los que los átomos rompen sus enlaces químicos y forman otros nuevos, cambiando la naturaleza de las sustancias que intervienen.

En una ecuación química se representan dos términos. En el primero, el de la  derecha, se escriben los reactivos, expresados mediante sus fórmulas químicas  correspondientes y separados por un signo más. Por otro lado, el término de la izquierda, en  el que aparecen los productos, también representados por sus formulas químicas  correspondientes y con signos más entre ellos. Entre ambos términos suele ponerse  una flecha que indica que se ha producido la reacción química correspondiente.

Las sustancias que hay antes de producirse el cambio y que desaparecen se llaman reactivos. Las sustancias que hay después de producirse el cambio y que aparecen o se generan se llaman productos.

El estado de agregación en una reacción química se indica poniendo detrás del nombre o la fórmula de la sustancia y entre paréntesis la notación siguiente:

  • Sustancias sólidas (s)
  • Sustancias líquidas (l)
  • Sustancias gaseosas (g)
  • Sustancias disueltas en agua (aq)

En este caso tienes la reacción química:

Mg (s) + 2 HCl (aq) -> MgCl₂ (aq) + H₂ (g)

Entonces, <u><em>en este caso los reactivos, con su correspondiente estado de agregación, son:</em></u>

  • <u><em>Mg: estado sólido</em></u>
  • <u><em>HCl: estado acuoso</em></u>

<u><em>Por otro lado, los productos, con su correspondiente estado de agregación, son:</em></u>

  • <u><em>MgCl₂: estado acuoso</em></u>
  • <u><em>H₂: estado gaseoso</em></u>

6 0
3 years ago
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