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spin [16.1K]
3 years ago
10

The Force of friction between an object and the surface upon which it is sliding is 12N. The weight of the object is 20N. What i

s the coefficient of kinetic friction?
Use equation Ffr=Uk(mg)
Physics
2 answers:
shtirl [24]3 years ago
7 0

Answer: The coefficient of kinetic friction is μ = 0.6

Explanation:

For an object of mass M, the weight is:

W = M*g

where g is the gravitational acceleration: g = 9.8m/s^2

And the friction force between this object and the surface can be written as:

F = W*μ

where μ is the coefficient of friction (kinetic if the object is moving, and static if the object is not moving, usually the static coefficient is larger)

In this case, the weight is:

W = 20N

And the friction force is:

F = 12N

Replacing these values in the equation for the friction force we get:

12N = 20N*μ

(12N/20N) = μ = 0.6

The coefficient of kinetic friction is μ = 0.6

Gekata [30.6K]3 years ago
5 0
Hope you have a good year!
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AleksandrR [38]

Answer:

h = 36.4 cm

Explanation:

given,

spring constant = 2.5 x 10⁴ N/m

compressed distance = 11.2 cm = 0.112 m

mass of the child = 44 kg

maximum height = ?

by energy of conservation

K.E_i +P.E_i= K.E_f + P.E_f

\dfrac{1}{2}kx^2 = mgh

\dfrac{1}{2}\times 2.5 \times 10^4 \times 0.112^2 = 44\times 9.8 \times h

\dfrac{1}{2}\times 2.5 \times 10^4 \times 0.112^2 = 44\times 9.8 \times h

156.8 = 44 \times 9.8 \times h

h = \dfrac{156.8}{44 \times 9.8}

h = 0.364 m

h = 36.4 cm

7 0
3 years ago
The wave function of a particle is exp(i(kx-omegat)), where x is distance, t is time, and k and co are positive real numbers. Th
Step2247 [10]

Answer:

Momentum, p=\hbar k

Explanation:

The wave function of a particle is given by :

y=exp[i(kx-\omega t)]...............(1)

Where

x is the distance travelled

t is the time taken

k is the propagation constant

\omega is the angular frequency

The relation between the momentum and wavelength is given by :

p=\dfrac{h}{\lambda}............(2)

From equation (1),

k=\dfrac{2\pi}{\lambda}

\lambda=\dfrac{2\pi}{k}

Use above equation in equation (2) as :

p=\dfrac{h k}{2\pi }

Since, \dfrac{h}{2\pi}=\hbar

p=\hbar k

So, the x-component of the momentum of the particle is \hbar k. Hence, this is the required solution.

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3 years ago
How much heat energy is required to raise the temperature of 5 kilograms of coal from 20°C to 220°C? A. 314 J B. 6,573 J C. 1,31
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Look at the diagram of the moon and three different paths that it could take. A planet with a moon in orbit. The moon has arrows
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is 3 and 2

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IBM has a fast computer that it calls the Blue Gene/L that can do '136.8
dmitriy555 [2]

Answer:

138.6 megacalculations

Explanation:

This is a pretty straightforward one.

All it needs is to convert the degree of measurement.

Dimensions in physics are attributed names, which state the power to which they're are raised. Just as how

Kilo and Mega means the numbers are raised to the power of 3 and 6 respectively. There also exists the ones that indicates how small, such as milli and micro, which are to the powers of -3 & -6.

The question says the IBM computer calculates at an astonishing 136.8 teracalculations.

Tera in physics means it's raised to the power of 12. Thus, the IBM calculates at an astonishing rate of

136.8*10^12 calculations per second.

We're then asked how many calculations it does in 1 micro second. Like I had highlighted earlier, 1 micro second is 1 raised to the power of -6. Or succinctly put,

1 micro second = 1*10^-6.

If the IBM does

138.6*10^12 = 1 second,

Then it does

x = 1*10^-6 second.

When we cross multiply, we have

138.6*10^12 * 1*10^-6, and that is

138.6*10^6 calculations, or say, 138.6 megacalculations.

The IBM does 138.6 megacalculations in 1 micro second, which is still astonishing, by the way

6 0
3 years ago
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