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Korolek [52]
4 years ago
11

What is the electric field strength inside the capacitor after insulating handles are used to pull the electrodes away from each

other until they are 1.0 cm apart? The electrodes remain connected to the battery during this process.
Physics
1 answer:
Bezzdna [24]4 years ago
3 0
This question apparently comes after an EARLIER one,
where you were told either the voltage across the same
capacitor or the total charge stored in it.  You can't answer
THIS one without that information.
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You and a friend are studying late at night. There are three 110 W light bulbs and a radio with an internal resistance of 56.0 Ω
Sliva [168]

Answer:

The total electrical power we are using is: 1316 W.

Explanation:

Using the ohm´s law V=I*R and the formula for calculate the electrical power, we can find the total electrical power that we are using. First we need to find each electrical power that is using every single component, so the radio power is:I=\frac{V}{R}=\frac{110 (v)}{56(ohms)}=1.96(A), so the radio power is: P=I*V=1.96(A)*110(v)=216(W), then we find the pop-corn machine power as: P=I*V=7(A)*110(v)=770(W) and finally there are three light bulbs of 110(W) so: P=3*110(W)=330(W) and the total electrical power is the adding up every single power so that: P=330(W)+770(W)+216(W)=1316(W).

8 0
3 years ago
When two resistors are wired in series with a 12 V battery, the current through the battery is 0.33 A. When they are wired in pa
MA_775_DIABLO [31]

Answer:

If R₂=25.78 ohm, then R₁=10.58 ohm

If R₂=10.57 then R₁=25.79 ohm

Explanation:

R₁ = Resistance of first resistor

R₂ = Resistance of second resistor

V = Voltage of battery = 12 V

I = Current = 0.33 A (series)

I = Current = 1.6 A (parallel)

In series

\text{Equivalent resistance}=R_{eq}=R_1+R_2\\\text {From Ohm's law}\\V=IR_{eq}\\\Rightarrow R_{eq}=\frac{12}{0.33}\\\Rightarrow R_1+R_2=36.36\\ Also\ R_1=36.36-R_2

In parallel

\text{Equivalent resistance}=\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}\\\Rightarrow {R_{eq}=\frac{R_1R_2}{R_1+R_2}

\text {From Ohm's law}\\V=IR_{eq}\\\Rightarrow R_{eq}=\frac{12}{1.6}\\\Rightarrow \frac{R_1R_2}{R_1+R_2}=7.5\\\Rightarrow \frac{R_1R_2}{36.36}=7.5\\\Rightarrow R_1R_2=272.72\\\Rightarrow(36.36-R_2)R_2=272.72\\\Rightarrow R_2^2-36.36R_2+272.72=0

Solving the above quadratic equation

\Rightarrow R_2=\frac{36.36\pm \sqrt{36.36^2-4\times 272.72}}{2}

\Rightarrow R_2=25.78\ or\ 10.57\\ If\ R_2=25.78\ then\ R_1=36.36-25.78=10.58\ \Omega\\ If\ R_2=10.57\ then\ R_1=36.36-10.57=25.79\Omega

∴ If R₂=25.78 ohm, then R₁=10.58 ohm

If R₂=10.57 then R₁=25.79 ohm

6 0
3 years ago
When an object loses electrons, it acquires a(n) ____________________ electric charge?
madam [21]
It acquires a positive electric charge.
4 0
4 years ago
What produces more severe burns, boiling water or steam?
Romashka-Z-Leto [24]

Answer:

steam

Explanation:

in \: steam \: the \: particle \: \\  \\  will \: have \: more \: energy \\  \\  because \: steam \: contain \: more  \\  \\ \: heat \: in \: the \: form \: of \:  \\  \\ latent \: heat \: than \: water \:  \\  \\ hope \: it \: helps

6 0
3 years ago
What is the total power in a circuit if the resistance is 800 and the voltage is 60 VDC?
Darya [45]
1.)    Power, P  =  V²/R  =  800²/45 =  4.5 W  (A).

2.)  Six Resistors in Series.
R = R1 + R2 + R3 + R4 + R5 + R6,    Since R is the same, R = 20

R total = 6*20 = 120 (D)

3.)  It is the current.  Series connection is to evaluate current.  (B)
3 0
3 years ago
Read 2 more answers
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