it's mass would double if it's volume doubled
Answer:
the speed of the sound in the air is 343.3 m/s
Explanation:
The computation of the speed of the sound in the air is shown below:
As we know that
Speed = Distance ÷ time
So, here speed be 515 m
And, the time is 1.50 seconds
So, the speed of the sound is
= 515 m ÷ 1.50 seconds
= 343.3 m/s
hence, the speed of the sound in the air is 343.3 m/s
Momentum = m • v
Original momentum = m • 10 m/s north
Final momentum = m • 15 m/s north
Change = m • (15 - 10) m/s north
Change = m • +5 m/s north
Change = +60 kg-m/s north
Answer:
Δx = 6.33 x 10⁻³ m = 6.33 mm
Explanation:
We can use the Young's Double Slit Experiment Formula here:

where,
Δx = distance between consecutive dark fringes = width of central bright fringe = ?
λ = wavelength of light = 633 nm = 6.33 x 10⁻⁷ m
L = distance between screen and slit = 3.7 m
d = slit width = 0.37 mm = 3.7 x 10⁻⁴ m
Therefore,

<u>Δx = 6.33 x 10⁻³ m = 6.33 mm</u>