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Korolek [52]
4 years ago
11

What is the electric field strength inside the capacitor after insulating handles are used to pull the electrodes away from each

other until they are 1.0 cm apart? The electrodes remain connected to the battery during this process.
Physics
1 answer:
Bezzdna [24]4 years ago
3 0
This question apparently comes after an EARLIER one,
where you were told either the voltage across the same
capacitor or the total charge stored in it.  You can't answer
THIS one without that information.
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lets say that an object of a certain volume has a certin mass. what happens to its mass when you double its volume?
lbvjy [14]

it's mass would double if it's volume doubled

7 0
3 years ago
A sound wave produced by a chime 515 m away is heard 1.50 s later. What is the speed of the sound in the air?
aliina [53]

Answer:

the speed of the sound in the air is 343.3 m/s

Explanation:

The computation of the speed of the sound in the air is shown below:

As we know that

Speed = Distance ÷ time

So, here speed be 515 m

And, the time is 1.50 seconds

So, the speed of the sound is

= 515 m ÷ 1.50 seconds

= 343.3 m/s

hence, the speed of the sound in the air is 343.3 m/s

6 0
3 years ago
A 12 kg object speeds up from an initial velocity of 10 m:s-1
amid [387]

Momentum = m • v

Original momentum = m • 10 m/s north

Final momentum = m • 15 m/s north

Change = m • (15 - 10) m/s north

Change = m • +5 m/s north

Change = +60 kg-m/s north

5 0
3 years ago
a water pump takes water through 12m. Water is discharged at the surface at the rate of 2Kg/s, and the discharge speed of each d
pickupchik [31]

Answer:

45

Explanation:

3 0
3 years ago
Red light of wavelength 633 nm from a helium-neon laser passes through a slit 0.370 mm wide. The diffraction pattern is observed
erica [24]

Answer:

Δx = 6.33 x 10⁻³ m = 6.33 mm

Explanation:

We can use the Young's Double Slit Experiment Formula here:

\Delta x = \frac{\lambda L}{d}\\\\

where,

Δx = distance between consecutive dark fringes = width of central bright fringe = ?

λ = wavelength of light = 633 nm = 6.33 x 10⁻⁷ m

L = distance between screen and slit = 3.7 m

d = slit width = 0.37 mm = 3.7 x 10⁻⁴ m

Therefore,

\Delta x = \frac{(6.33\ x\ 10^{-7}\ m)(3.7\ m)}{3.7\ x \ 10^{-4}\ m}

<u>Δx = 6.33 x 10⁻³ m = 6.33 mm</u>

8 0
3 years ago
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